Basic Graphs query (1 Viewer)

[vds700]

Hi I was just doing some notes for graphs, and it says in the syllabus u need to know y = x^(1/3) I entered this in winplot and have attached what it came up with. Just wondfering if its correct, as i thought the cube root of negative numbers was defined, but the graph suggests otherwise.

Cant find the graph in the textbook either.

 

[Templar]

It should be defined for all real x

It's odd, so just rotate that bit to the negative half.

 

[vds700]

ok so has the program made an error or something?

 

[Affinity]

it's how they implemented it.. the program doesn't thinkof 1/3 as 1/3 exactly but as float close to 0.33333333333 then the POWER function in programs would return complex numbers(or it may be underfined).. so you don't get that part of the graph..
better programs take this into consideration

 

[vds700]

it's how they implemented it.. the program doesn't thinkof 1/3 as 1/3 exactly but as float close to 0.33333333333 then the POWER function in programs would return complex numbers(or it may be underfined).. so you don't get that part of the graph..
better programs take this into consideration

ah ok. Dont really get what u mean by the power function returning complex numbers, but thanks for your help anyway.

I just tried entering y^3 = x and it produced the whole graph.