hsc3hard5me
Member
- Joined
- Oct 22, 2014
- Messages
- 78
- Gender
- Male
- HSC
- 2015
Can someone explain how this works, this is one of the only common types that always gets me
^ nope
as if, that can't be righta is 8!/(5!3!)
b is 1/28
inb4MIFas if, that can't be right
what t/b or resource is this?
inb4MIF
What year?MIF? Close boys, Sydney boys trial paper lel.
Correct me if I'm wrong but these table questions take into account position, so you cant use combination?i) Choose 3 people to sit on the 3-seat-table. Then arrange both groups accordingly. 8C3 x 2! x 4!
ii) 1 - P(couple sit together) = 1 - [ P(both on 3-seat-table) + P(both on 5-seat-table)]
= 1 - [ (6 x 2! x 4!) + (6C3 x 4! x 2!) ] /(result from i)
2000What year?
Part (ii) is a 2 Unit question. It doesn't need any perms and combs.Correct me if I'm wrong but these table questions take into account position, so you cant use combination?
Can you explain o;Part (ii) is a 2 Unit question. It doesn't need any perms and combs.
It is just (3/8)*(5/7) + (5/8)*(3/7)
3 chances in 8 of the male being placed at the table of 3 AND THEN 5 chances in 7 of the female being placed at the table of 5Can you explain o;