D Dylanamali Active Member Joined Jul 7, 2009 Messages 1,248 Gender Male HSC 2011 Mar 11, 2012 #1 If possible, sketch the graph of In(In(sinx)). Comments?
nightweaver066 Well-Known Member Joined Jul 7, 2010 Messages 1,585 Gender Male HSC 2012 Mar 11, 2012 #2 I don't think you can.. y = ln(sinx) gives a graph thats <=0 so you cannot graph y = ln(ln(sinx)) as there won't be any defined points.
I don't think you can.. y = ln(sinx) gives a graph thats <=0 so you cannot graph y = ln(ln(sinx)) as there won't be any defined points.
D Dylanamali Active Member Joined Jul 7, 2009 Messages 1,248 Gender Male HSC 2011 Mar 11, 2012 #3 yeah that's what I thought... because the sine graph only exists between 1 and -1.. and In(1) = 0 and In(<1) < 0. But i think the question is worth 5 marks.. this is university maths btw, not 2u.
yeah that's what I thought... because the sine graph only exists between 1 and -1.. and In(1) = 0 and In(<1) < 0. But i think the question is worth 5 marks.. this is university maths btw, not 2u.