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Advanced Logarithms Question HELP. (1 Viewer)

nightweaver066

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I don't think you can..

y = ln(sinx) gives a graph thats <=0 so you cannot graph y = ln(ln(sinx)) as there won't be any defined points.
 

Dylanamali

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yeah that's what I thought... because the sine graph only exists between 1 and -1.. and In(1) = 0 and In(<1) < 0.

But i think the question is worth 5 marks..
this is university maths btw, not 2u.
 

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