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2x Maths Questions (1 Viewer)

Alkanes

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man this guy can gtfo. atleast post up the solutions. i asked him if my solutions were right. doesn't even reply... go to hell.
 

SpiralFlex

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He's just a bit caught up with the first question. Your solution is right.
 

AAEldar

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This is what I did, I can't see what I did wrong, fresh set of eyes might.

 
Last edited:

AAEldar

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I know it doesn't, that's why I posted it to see if anyone sees why it doesn't fit.

Ohexploitable: I re-arranged them?
 

SpiralFlex

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I think when you subbed 1 into 7, you did it wrong. Shouldn't it equal to -2?
 

SpiralFlex

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Uh, I thought it was:

3 + 2(pq + pr + qr) = -1

2(pq + pr + qr) = -4

(pq + pr + qr) = -2
 

AAEldar

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Ah I know where I went wrong. Supposed to be:



That sucks.

Wait, now I don't even know. I'm so confused.
 

Alkanes

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hmm i cbf doing it.. but have any of u guys tried changing equation (1) p^2 + q^2 + r^2 = 3 into (p+q+r)^2=3 then change it into ==> p+q+r = root 3.. Here's something that might help, you guys do it i cbb. =)
 

SpiralFlex

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hmm i cbf doing it.. but have any of u guys tried changing equation (1) p^2 + q^2 + r^2 = 3 into (p+q+r)^2=3 then change it into ==> p+q+r = root 3.. Here's something that might help, you guys do it i cbb. =)
That's what AAElder did.
 

AAEldar

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hmm i cbf doing it.. but have any of u guys tried changing equation (1) p^2 + q^2 + r^2 = 3 into (p+q+r)^2=3 then change it into ==> p+q+r = root 3.. Here's something that might help, you guys do it i cbb. =)
You can't just pull the powers of 2 out the front.
 

Alkanes

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oh did he ? ahh my bad i didn't read wat others did except for exploitable where he was using complex numbers or someshit lol
 

SpiralFlex

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I am adamant I came across this question the other day.
 

Alkanes

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ahh yep yep wtf was i doing... sorry brain frozed for a minute.
 
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I'll say this once again, I solved it in the complex field, those are the only solutions, there are no real solutions.
 

SpiralFlex

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I wonder who would be the first to get this question! Race ya. ;)
 

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