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2026 HSC CHAT (7 Viewers)

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View attachment 49460
how do u draw the tree diagram for this cause there's married vs unmarried and then women vs male
ok bump. I know how to do a but B is very confusing. mY teacher put worked solutions up but I don't get when u draw the 2nd tree for when they pick the second person, (if first person is married woman). Like how does it affect that treeScreenshot 2025-10-17 at 2.40.50 pm.png

Screenshot 2025-10-17 at 2.41.08 pm.png
 

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f7eeting

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ok bump. I know how to do a but B is very confusing. mY teacher put worked solutions up but I don't get when u draw the 2nd tree for when they pick the second person, (if first person is married woman). Like how does it affect that treeView attachment 49521

View attachment 49522
wait what the hay bahaha are we in the same class?? lol
anyways, if you know the first person picked is a woman, then that means that there's one less person you can choose (bc u cant choose that woman again) meaning that the total amount of people goes from 66 to 65.
the number of males stays the same, so the number of married/unmarried men is unaffected and therefore the chance of a man being unmarried is 21/65.

to go a little further, since a married woman has been chosen, you can also consider how that would affect the sample space of women. it will reduce the total amount of people to choose from by 1, but also reduce the number of women in specific by 1, making the chance of choosing a woman 31/65 (which adds up)
this also means that the number of unmarried women is unaffected, and will be 13/31 whilst married women is affected and will be 18/31

if u wanna practice these kinds of calculations, these are multi-stage probability questions where the events are dependent on each other, like choosing something without replacement
 

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