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2.8.1 Dot Point Help! (1 Viewer)

freezeice04

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A rocket has mass 400kg, 75% being fuel. It develops a thrust of 8000N. Calculate its initial acceleration.

How do I do this?
 
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Remember, thrust is constant...you're only using f=ma, i.e 8000 = m*a i.e 8000 = 400*a, etc. this also shows, as the fuel is used up, the acceleration of the rocket increases
 

freezeice04

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Remember, thrust is constant...you're only using f=ma, i.e 8000 = m*a i.e 8000 = 400*a, etc. this also shows, as the fuel is used up, the acceleration of the rocket increases
The answer says its 10.2m/s^2, not 8000/400m/s^2
 

freezeice04

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Well the answer has something different. Can someone clarify if the answers is wrong or not? I have a feeling it has something to do with momentum though.
 

TheTutorBot

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there is nothing relating to momentum in the question (except that we use the fact that force = momentum X velocity)
 

freezeice04

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I don't think doing f=ma is right since there is another similar question and it has a completely different answer.
Dotpoint 2.8: Analyse the changing acceleration of a rocket during launch in terms of Law of Conservation of Momentum and the forces experienced by astronauts.
 

freezeice04

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Wait I think I know now, its F=ma then you minus 9.8 (from gravity).
 

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a= T-mg/m

T = 8000N
m = 400kg
g = 9.8m/s/s

a = 8000 - ( 400 x 9.8) / 400
a = 10.2 m/s/s
 

TheTutorBot

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Wait I think I know now, its F=ma then you minus 9.8 (from gravity).
Never subtract g from an answer...I don't recall a case where you have to anywhere in physics.

and ohexploitable, who actually knows that formula? (and why didn't I think of it?)
 
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Never subtract g from an answer...I don't recall a case where you have to anywhere in physics.
Kay, say there is a 1000kg car and I apply a force of 1N upwards, since I don't subtract mg then that means there is a net force upwards. This means I can lift a one tonne car with a finger.

brb, I'm gonna try and lift up my parent's car lols.
 

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