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    More Help with Past HSC Probability Questions Needed!

    hahah think I got it Probability that he wins is P(he wins)/P(he wins)+(P he doesn't win) I used the notion of limiting sums, thanks, I made the number of throws = 10 So P(he wins) = (13/18)^10 * 1/9 P(he doesn't win) + P(he does win) = (13/18)^10 * 3/18 + (13/18)^10 * 1/9 Divide those two...
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    More Help with Past HSC Probability Questions Needed!

    yeah ok ,sorry my bad drongoski :( Also regarding the question, I'm not sure if these are 2U or 3U hsc questions, but I'd always been under the impression these were 2U? Unless this is the norm for 2U?
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    More Help with Past HSC Probability Questions Needed!

    hey hey hey, that's kind of unfair saying that don't you think? I live in Minto by the way, far south-west of sydney, and every guy I see on BOs offering Tutoring services, lives in Bankstown, Parramatta, Epping, Blacktown, and Fairfield, all on the wrong side of Sydney, for me. I know ppl like...
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    More Help with Past HSC Probability Questions Needed!

    Hey thanks so much, but still don't understand why the sample space must be restricted... :S But ignoring that, could you please help me on a HSC question which I don't understand the WORDING of. Q. David has invented a game for 1person. He throws 2 ordinary dice repeatedly until the sum of...
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    More Help with Past HSC Probability Questions Needed!

    Hi just a few questions I need help with. Q1. A bag contains 2 red balls, 1 black ball, and 1 white ball. Andrew selects one ball from the bag and keeps it hidden. He then selects a second ball, also keeping it hidden. (i) Draw a tree diagram to show all possible outcomes. Already done, too...
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability Any confirmation advice please? thanks?
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability So I guess the best way to calculate P(AB) in an exam, or anyother situation, would be look at any possible outcomes that match up with both Events A and B, i.e. outcomes that are the INTERSECTION of A and B...
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability Could I just ask why in Q2, A and B are statistically independant, yet it in Q3, A and B, they aren't statistically independant?
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability could someone please look at my above post? Thanks
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability Ok so I guess there is conditional probability in questions involving item not being replaced??[U] Could you please relate the conditional probability to Q2 and Q3 in my 1st post, because for Q2, I don't...
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability Correct me if I'm wrong, but isn't that the same as mutually exclusive events, that is, occurrence of one event automatically excludes all others. If I'm wrong, what is the difference between this condition...
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability No, I was asking for non-mutually exclusive events, e.g. look at Q3. In Q3, P(A) = 10/30, P(B)= 4/30 Therefore P(A) * P(B) = 2/45 BUT, P(AB) = 1/30 because 21 is the only number is the set{1to30} that is a...
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Re: Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability Looking at Q2 and Q3, you can see they are the same, except for what it is asking of you, i.e. Q2 asks for multiples of 3 and 5, and Q3 asks for 3 and 7. So why does P(AB)=P(A)*P(B) work for Q2 but not Q3?
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    Don't understand concept of P(AB) in non-mutually Exclusive Events - Probability help

    Hi guys, I need help with understanding an crucial concept regarding P(AB), i.e. the intersection of events A and B, in relation to non-mutually exclusive events, and other probability questions. It's known for non-mutually exclusive events, P(A and B) = P(A) + P(B) - P(AB) All this time I...
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    Australian Open Thread

    pFFT, murray's gonna win, without a doubt.
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    Australian Open Thread

    Yeah, I like Djokovic more than Federer, and depsite Djokovic having beaten Federer a couple of times here and there, and despite Djokovic's immense skill on the hard court, Federer is just MAGIC.
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    Australian Open Thread

    DJOKOVIC!!!!!!! OMG HE WON IN STRAIGHT SETS. Kinda felt sorry for Berdych, he's a good guy...
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    Probability question involving poker machines - need help

    So it's a problem on behalf of Jones and Couchmann? Because this is the first mistake I've seen in the book...
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    Probability question involving poker machines - need help

    Anyone else got anything, perhaps if I did something wrong, or misunderstood the question?
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    Australian Open Thread

    And her manly features.
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