MedVision ad

Search results

  1. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Yeh true x can't = 0 though that's for sure
  2. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon It wouldn't have a limiting sum yeh ? Because |r| is not <1
  3. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon X=pi/2 silly mistake
  4. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon X=pi/2 my bad
  5. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon 1-cosx= sin^2(x)/cos(x) Cos(x) - cos^2(x)= sin^2(x) Sin^2(x) + cos^2(x)=1 Hence, cos(x)=1 X=pi/2:)
  7. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Look at the graph/ garden. Then look at the last 5th function value it's on ground point with f(last) so it's =0
  8. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon I didn't assume.. The last function value at f(last)= 0
  9. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Dom 2 < x < 3 including Range: 0 < y < 1 including ??
  10. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon What is the domain and range for Y=square root(9-x^2)
  11. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon H=5 Area= 5/2(f(x1) +f(xn) + 2(f(x between)) Area= 5/2(2+0+2(4.5+5.1+3.6)= 71 C
  13. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Simplfy: sin(2pi-x) Sin(pi/2 -x)
  14. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Equation x^2 - 6x -8y= 23 i) Find the coordinates of the focus ii) what is the equation of directrix
  15. B

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon Show that sec(x) - sec(x)cos^4(x) = sin(x)tan(x) 1 + cos^2(x)
View older results
Top