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yes, with what Smile12345?

Draw that beautiful circle with all ur heart! Important info for circle: *Centre is (2, -1) radius is 3* ^Highlight this blank space and u will see radius and centre of ur circle Since less than - colour inside of circle and since less than and NOT EQUAL, we dot the circle

Thank you sir

1. Practice 2. I think this is 3U maths...(maybe)

Re: MX2 Integration Marathon $Let I = $\int \frac{dx}{(x+\sqrt{x^2 -1})^2} = \int \left ( \frac{1}{x+\sqrt{x^2-1}} \right )^2 dx \\ \\\therefore I = \int \left ( \frac{1}{x+\sqrt{x^2-1}}.\frac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} \right )^2dx \\\\ I = \int (x-\sqrt{x^2-1})^2dx \\ \\I = \int (2x^2...

lol

1≠3 try it by subbing in values of n (integers)

40) (i) Alternate angles somewhere Then apply a specific trig ratio that involves x and 200 (ii)Differntiate theta with respect to x (utilising equation found in part (i)) \frac{d\theta}{dx} = \frac{\frac{-200}{x}}{1+\left ( \frac{200}{x} \right )^2} We want TIME, and to get rid of x...

no problemo, yes i do 4U maths

Re: HSC 2013 4U Marathon Here, Makematics gave u a great method

haha yeh i did not think about other topics lol

It is u you will be the legend at the end of the day

misread..thought this was AMC

I have PM'd u NizDiz

LOL! HAHA, i have not paid for it....

Cooling and ambient temp, lets think of Newton's Law of Cooling (a beautiful thing...) T = T_0 + Ae^{kt} Where T_0 is a confounding factor A, k is consant t is time in minutes (according to Q) T is temperature of the body Interpretation of question: "a room with a surrounding air temp. of...

Very good

haha ok, cool, thanks , and i feel more comfoortable using combinations

P= \frac{1000}{1+ce^{-1000t}} \\ \\ \frac{dP}{dt} = \frac{1000000ce^{-1000t}}{(1+ce^{-1000t})^2} \\ \\ $Note: P = $\frac{1000}{1+ce^{-1000t}}, \therefore ce^{-1000t} = \frac{1000-P}{P} \\ \\ \therefore \frac{dP}{dt} = \frac{1000000\left ( \frac{1000-P}{P} \right )}{(1+ \frac{1000-P}{P})^2} \\...

I didnt actually use quotient rule, but yeh u can use quotient rule