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  1. omgmynameislong

    lol how do u do q12 of senders hwk for polynomials.

    lol how do u do q12 of senders hwk for polynomials.
  2. omgmynameislong

    ESL scales higher than STANDARD?

    Standard and Advanced scales the same. Standard and Advanced ALIGNS differently and because of the aligning, it is a lot harder to get band 6 in standard than advanced. BoS does the aligning while UAC does the scaling. Why the fuck wouldnt their scaling be the same when half our HSC...
  3. omgmynameislong

    Hi rgay.

    Hi rgay.
  4. omgmynameislong

    James Ruse?

    hoohoho i see what u did there.
  5. omgmynameislong

    zomg atar estimate???!!??

    lol fobs doing general maths
  6. omgmynameislong

    Limits help

    Long divide.
  7. omgmynameislong

    integration help

    inverse sin(x/2)
  8. omgmynameislong

    HSC - 2010 Timetable

    wait for 1 more day.
  9. omgmynameislong

    Stupid Exam Timetable..

    why dont u stop bitching. Q________________________________Q. no1 gives a shit about your timetable or op's.
  10. omgmynameislong

    Possible to get 72+ Atar?

    if trollmeter says >10 then u should get 99 atar if <10 then tafe.
  11. omgmynameislong

    domain

    ah i see lol. Was thinking all real x but then roots are bigger than 0 :\. ty.
  12. omgmynameislong

    domain

    lol i meant x^2 -1 inside the brackets so... inv tan (x^2-1)^1/2
  13. omgmynameislong

    domain

    What about inv tan (2x-1)^1/2
  14. omgmynameislong

    domain

    Whats the domain of inverse sinx . inverse cos x/2
  15. omgmynameislong

    Question about becoming Maths Teacher.

    tell him to ask his math teacher.
  16. omgmynameislong

    Polynomial

    i+3-4i-2 =1-3i
  17. omgmynameislong

    Polynomials ....

    iii) If the roots are distinct then it passes through x axis 3 times. Therefore f(u) must be a negative value and f(v) must be a positive value. A positive value times a negative value is alwyas lesser than 0. therefore f(u).f(v)<0 f'(x) = 3x^2 +b = 0 therefore x= +(-b/3)^1/2 and...
  18. omgmynameislong

    polynomials help D:

    3a+3b=3 a+b=1 a=1-b 2a^2 + ab + 2ab+ 2ab+ 4ab + 2b^2=-8 2a^2 + 2b^2 + 9ab = -8 2[(a+b)^2 -2ab] +9ab=-8 2(1-2ab)+9ab=-8 2+5ab=-8 5ab=-10 ab=-2 (1-b)b=-2 b-b^2=-2 b^2-b-2=0 (b-2)(b+1)=0 therefore b=2, a=-1
  19. omgmynameislong

    4 Unit Revising Marathon HSC '10

    integrate xlnx
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