Search results

And the rest of the 'proof' is thus: Let the number be n We know that two of the 4 smallest divisors will be 1 and 2. If another is 3, then we have n = 1 + 4 + 9 + a^2 = 14 + a^2. a/n, so a/14 (as a/a^2). We check 7 and 14, and they don't work. Therefore 3 does not divide n We check...

In the limit as x approaches infinity, x + x = 2x + 1 Therefore, in the limit as 2 approaches infinity, 2 + 2 = 5

Yeah, I know now. I thought he was because he mentioned meeting chris at the talented students day and I saw Jordan there, and I didn't think many people from Wollongong would be there.

Hmmm, are you Jordan? I'm Graham, I was just wondering why 'whitey'.

If you were rigorously proving this, you'd have to first prove that f(a) = f(b) ==> a = b, but that isn't too hard. f(a) = f(b) Therefore f(f(a)) = f(f(b)) Therefore 6a - 2005 = 6b - 2005 Therefore a = b

What do you get when you cross an elephant and a monkey? A vector with magnitude Elephant Monkey sin theta and perpendicular to both of them What do you get when you cross an elephant and a mountain climber? Don't be silly, you can't cross a vector and a scalar Also, see my sig.

This is correct.

Whitey? (Hmmm, apparently I need 10 characters)

In other words, half empty (which is the same as half full) is not the same as half of empty, because half of empty is still empty.

It was pretty hard this year. For the senior, the last 5 answers were 80, 401, 20, 5 and 13. (The number for the last one is 130)