im gunna go out and by myself a maths textbook tomoz and was wondering what to get i already got cambridge. and if i was to by fitzpatrick should i get the extension one or advanced one( which one is more relevant form prelim)
we just had the half yearlies for maths. now the test was so surprisingly hard and since my teacher is an author didn't help either. i think i might've came 2nd with a approx mark of 22/45 what does this mean.
hello i was wondering how do we work out the school rankings if we know the results and what they are out of.
for example i got 18/23 for first assessment and then 37/50 and the other person got 21/23 and 31/50. so who get first and who gets second. forgot to add they are both worth 20%.
hello, i am in prelim but i just wanted to know where i satnd in terms of atar according to my ranks.
eng adv-2/70
maths adv-4/70
maths ext-5/25
chem-2/40
bio-4/45
and my school rank is shit like 350 i think
i have reached the end of my past papers and there is one more question which i just cant seem to get. i kinda know how to do it but yeah.
find the equation of any line which makes an acute angle of 15 degrees with 2x-2y+7=0.
what textbook is this in, i think it was in my half yearlies. all u need to do is balance the equation. them multiply the mole of magnesium oxide depending on them mole ratio to get the moles of the other components. after this u use the mole formula to calculate the mass.
that is the way my teacher showed me but she showed us the pattern which we can use. but i posted the question on bos since i didn't want to remember the pattern.
i was trying to solve this question when i just couldn't find how.
without solving the polynomial X^3-X^2-X+1=0 WITH ROOTS A,B AND C. find the value of A^3+B^3+C^3
i just got my results for my prac assessment and was really disappointed but i don't know if i deserved to get the marks i did.
well there was three pracs
part a i got 16/17
part b i got 12/15
and for part c my results were completely wrong so everything i did related to my results and hence...