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u used DELTA = 0 and got that? DELTA = 0 came out extremly long... (cannot be done in an exam) if you used that method can you post your working... also what about perpendicular distance since the perpendicular distance will be the radius wouldnt | ax + by +...

the answer is 1 - Pi/2 right? why does everyone here always do things so weirdly... i just did subsititution then parts...

its been a week... just ask him

come on.... why cant anyone solve this.... i mean shafqat 5th in the state lets go... what about all the people that are confident of getting a top 10 in state placing this yr in the big names in '05 thread... ngai? wanna solve it ?:) ANYONE......

hey yea sorry, u cant do that this is because the point P is on the hyperbola not the circle so asec@ btan@ does not lie on the circle so u cant substitiute it in the gradient... thats what i tried to do and u should get sec@ = 1/e if u did all this properly (which obviously would give u...

P (asec@,btan@) lies on the hyperbola x²/a² - y²/b² = 1. the tangent at P is also a tangent of a circle. (x - ae)² + y² = a²(e²+1) show that sec@ = -e (btw delta = 0 is too big ... so perpendicular...

shafqat Q4 please...

is this the one with just 5 questions or so... shafqat ofcourse u would've managed a prize mate, cos ur fucking good. PS do Q4 from my conics thead!

hey um, the site you have with the standard package is passworded and all the standard packages have a 10.XXX.XXX.XXX link which is internal (so would only work on their school computers)

it isnt, i havnt seen a question like this either... e^ix gets mentioned in most of the text books and your teacher might have talked about it.

yea math.com this integral is beyond our syllabus

mmmm currently ngai is top of the state for last yr.... so i would trust everything he says :P also your integration cant be solved with high school math... Integrate Result

no, question 4 is new, i just put it up..

indeed.. btw feel free to look at my conics thread and solve Q4

yea i dont really know what he is going on about though... i think it might be the formatting ..

<b>Please try <i>QUESTION 4</i> for me guys</b>

yea what slide rule said is right... basicly the question came with a definite integral.. and it said to prove it equals 0. but i didnt put the definite integral up and only said to evaluate...

yea you must use the substitution..

2 quick questions: use substitution u = 1/x and evaluate: ln(x)/(1 +x^2) second question evaluate: x* squareroot(6-x) dx for the second one i tried using a subsitution like x = 6sin^2@ so i could get rid of the square root and i can get an answer but its in cos@ and sin@ and...

wow, you make the best decisions... no wonder you came what... 5th in the state...