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*love* crappy love songs =]. they make you feel so much better somehow. or make you cry, depending on your frame of mind. i just love it. haha.

yeah, i live in the left hand column. way too many rebound regrets.

i changed schools at the beginning of year eleven and my current boyfriend asked me out before i'd even been there a month. we've been together since then. and yeah. i'm not one of those people who always has to have a boyfriend, it kind of just works out that way. my previous relationship was...

4. a. _{5}^{6}\textrm{P} 4. b. 5x4x3x2x3 = 360 you start with the last three, because there are three even numbers, and an even number must be last for the whole number to be even, then, there are 5 numbers left which must consequently be placed in the remaining positions, with one less number...

yeah. most random thing to just chuck them on the series. kind of annoying.

what school do you go to? is it selective? partially selective? what is the overall calibre of your grade?

(Y) is the msn emoticon for thumbs up =]].

blehh. you're right. far out i really should not have neglected chem.

pretty sure you can, your school is just a number. the markers don't know what school you're from and it's all in the same paper.

oh yeah, sorry, i meant the question. i meant that i'll do that for the whole paper, write that line out in each question. my bad.

haha. this. i don't have a desk.

we had a conference thing with an mx2 marker and he said if you make some indication that cis = cos + isin then it's fine to use cis. i'll write, eg. cis(pi/2) where cis(pi/2) = cos(pi/2) + isin(pi/2) and then use cis for the rest of the paper.

haha. thanks for that.

sorry, i fell straight to sleep almost with my computer on my lap. i still had notes and books everywhere on my bed. haha. sorry!

umm second part, t&u are equal to -2 and 3, then show by distance formula that two sides are equal. my head is hurting too much to type the whole solution out.

aww it took me so long to do that on eqn editor. if you still don't have an answer for it in the morning i'll help out, but it is way too far past my bedtime.

b. i. tx-at^{2}=ux-au^{2} tx-ux=at^{2}-au^{2} x(t-u)=a(t-u)(t+u) x=\frac{a(t-u)(t+u)}{(t-u)} x=a(t+u) \therefore y=t[a(t+u)]-at^{2} y=at^{2}+atu-at^{2} y=atu \therefore \textup{intersection point}(a(t+u),atu)

and it's just getting worse. *joy*

yeah, i really agree. i got into the top 0.3% of that westpac maths comp in y8 and did some maths enrichment program where i got sent questions and had to send my solutions back to some guy in french's forest. that's all i remember. and 2u maths is a piece of cake. so pretty sure i could have...

you never answered the person doubting your legitimacy?