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LOL. That makes sense.

You should see the creative.

5 = 3 ?

HO HN HF ^^ what you want for hydrogen bonding.

Unsure what that means. I seperated it in to a GP, 1 + 1/2 + (1/2)^2 + ... And applied the sum of gp three times. I noticed a pattern and was able to deduce what the result would look like if I repeated this. Applied GP sum again, n-> infinity and I got my answer.

My working out is pretty messy and there's probably a much quicker way lol. Waiting on Spiral for a nice solution.

Ended up with 4.. unsure though..

Re: 2012 HSC Mathematics Marathon!

Re: 2012 HSC Mathematics Marathon! x = 0 lies in x < 1/2, x > 3 and it doesn't hold for the original inequation. If you test x = 2, you'll end up with 10/3 > 3 which is true so the answer is that domain, i.e. 1/2 < x < 3.

Re: 2012 HSC Mathematics Marathon! lol what.. This parts incorrect. If you sub in x = 0, doesn't LHS become 0 which is < 3?

Was quite pricey last time i got it (a few years back) and the burger was pretty damn big.

Let u = 4 - y, etc.

Looks like Jones & Couchman.

How about this. :) Extend BC such that it meets DE at M. \angle DCM = 180 - y $ (angles on a straight line, MB)$ \angle BME = x $ (alternate angles, AB parallel to DE)$ x = 180 - y + z $ (exterior angle of triangle DCM)$ \therefore x + y - z = 180

Yes he did. I love how almost all of your posts are you reposting the same question in to multiple threads that are not related.

My friends switched to Casio because Sharps were slow for them.

Go for the Casio fx-82AU or Casio fx-82AU Plus

Re: 2012 HSC MX2 Marathon How can a modulus result in an imaginary number? lol..

LHS = (cosA + \frac{1}{cosA})\times \frac{cosA}{sinA} = \frac{cos^2A}{sinA} + \frac{cosA}{sinAcosA} = \frac{cos^2A + 1}{sinA}

This seems quite useful too. http://www.wiley-vch.de/books/biopoly/pdf_v04/bpol4003_53_68.pdf