Re: HSC 2015 4U Marathon
so since A.B.Y are the roots of x^3 + 3x^2 - 4x + 5 = 0, then: A,B,Y are values of x
-> Rearranging: x^3=-3x^2 +4x -5
so, A^3 + B^3 + Y^3 = -3A^2 +4A -5 - 3B^2 +4B -5 - 3C^2 +4C -5 = -3(A^2+B^2+C^2) +4(A+B+C) -15
->A^2+B^2+C^2 = (A+B+Y)^2 - 2(AB +BC +AC) = 17...