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I got it before the holidays.

It is all to do with your degree of perfection you get to when you study. Being able to study well is also a skill that can be developed. Try to establish a good study habit and not to leave things until the last minute (by last minute, I mean last few days). This means you just need to keep up...

It's a general science skills test. It tests you on how well you read data, etc. Don't worry about it. It's the EASIEST competition ever.

n x (n – 1) x (n – 2) x ... x k x ... x 3 x 2 x 1 ----------------------------------------------------- (n – k + 1) x (n – k) x ... x 3 x 2 x 1 =n!/(n-k+1)! =nP(k-1) =n(n-1)(n-2)...(n-k+2)

Q3. sin^(-1) ?= tan^(-1) (x/sqrt (1-x^2)) Construct a right-angled triangle with an gle theta and adjacent side sqrt(1-x^2), opposite side x, hypotenuse 1. Then tan^(-1) (x/sqrt (1-x^2))=theta=sin^(-1) ? sin theta=x=? The ? mark represents the variable or constant you didn't write.

lol... acid+acid...

$Let y=x^x \\lny=ln(x^x) \\lny=xlnx \\\frac{\frac{dy}{dx}}{y}=lnx+1 \\\frac{dy}{dx}=x^x(lnx+1) \\$Q: Evaluate \int_{0}^{\frac{\pi}{4}}(cosx+secx)^2dx

I really hope so. But thinking about year 11, I started with a crap mark/rank in chem and climbed up to the top so rank/mark may indeed change dramatically.

I would go with (C) if the total no. of employees refer to the number in that particular year, but (D) if it refers to any year as the question did not say "the total number of employees in the year."

\frac{1}{\sqrt[3]{2}+1} \\=\frac{\sqrt[3]{2^2}-\sqrt[3]{2}+1}{(\sqrt[3]{2}+1)(\sqrt[3]{2^2}-\sqrt[3]{2}+1)} \\=\frac{\sqrt[3]{4}-\sqrt[3]{2}+1}{2+1} \\=\frac{\sqrt[3]{4}-\sqrt[3]{2}+1}{3} \\$Q: Explain why f(x) has to be a linear function for \int e^{f(x)}dx=\frac{e^{f(x)}}{f'(x)}+C$ to hold true.

\int_0^\frac{\pi}{2}(1+\frac{1}{2}sinx)^{-1}dx \\=2\int_{0}^{\frac{\pi }{2}}\frac{1}{sinx+2}dx \\=2\int_{0}^{\frac{\pi }{2}}\frac{2-sinx}{4-sin^2x}dx \\=4\int_{0}^{\frac{\pi }{2}}\frac{1}{3sin^2x+4cos^2x}dx+2\int_{0}^{\frac{\pi }{2}}\frac{d(cosx)}{3+cos^2x} \\=4\int_{0}^{\frac{\pi...

\int_1^2 \frac{(x+1)dx}{\sqrt{-2+3x-x^2}} =\int_1^2 \frac{(x+1)dx}{\sqrt{\frac{1}{4}-(x-\frac{3}{2})^2}} \\u=x-\frac{3}{2} \\$Using the substitution above or otherwise, finish it.

I see. That's why you could learn how to fail in an exam so quickly. Good luck with failing all your subjects.:haha:

One of my friends looked at the answer sheet of a guy who does pretty well in a particular subject (in top 3, I think) and changed one of his answers accordingly. Although he had to turn 180 degrees around to do so, the supervisors didn't catch him. It was funny because that question had some...

Your trial will probably contain the option+1st+2nd core modules and a little bit of the 3rd module. I.e. After the trial, you'll keep learning new Chemistry stuff until the actual HSC. (The same with Physics)

Re: 回复: Re: 回复: Re: 回复: Re: 回复: Re: integration But one of my friends who came from China during Year 11 had learnt differentiation in China.

Any technique may be used (BUT DON'T USE ADJECTIVES AS A TECHNIQUE) if it relates to belonging. Whatever you know of, use it if you know that it addresses the AoS. The reason why you shouldn't use adjectives as a separate technique is that we are talking about a Year 12 level English, even if it...

Re: 回复: Re: 回复: Re: 回复: Re: integration They do differentiation, but not integration in high school

It is not easy to say you should definitely drop a subject, but if you have to, I'd suggest dropping physics is the best option. Reasons are: 1. You seem not to like it a lot. 2. Time is precious and it is the most time consuming. 3. If you were correct in saying "most ppl in other class got...

A Molar heat of combustion is the heat produced when one mole of a substance is burned under standard temperature and pressure Not sure, is that enough? With the product being carbon dioxide gas and liquid water. Plus you need to say COMPLETE combustion Q Explain what is meant by a...