\\$Let the centre be C(x,y).$ \\\therefore PC^2=PQ^2 \\(x+2)^2+(y+1)^2=(x-5)^2+(y+2)^2 \\x^2+4x+4+y^2+2y+1=x^2-10x+25+y^2+4y+4 \\y=7x-12 \\$sub this into 3x+y+2=0 \\x=1 \\y=-5 \\ \\Radius^2 \\=PC^2 \\=(x+2)^2+(y+1)^2 \\=25 \\ \\$Hence the required equation is (x-1)^2+(y+5)^2=25.