Search results

No, polynomials. Rational roots.

You don't need to use it though. Eg. if you use the sub. u^2=x then you can differentiate the 'x', ie. dx/du=2u so dx=2u du. or if you use implict differentiation, then 2u du/dx =1 so dx=2u du.

Hey all, Does anyone know what the symbol "|" means in mathematics? eg. s|an

I see... Do you teach all levels of mathematics?

*Sigh*, you just have to make a big issue, don't you? No, I wont be pointing out spelling errors in the whole website. But I think it is worth noting in a post that a tutor offering his/her professional services. It was more of a simple reminder to help them and correct their post... but no...

I couldn't care less how good she (or anyone else for that matter) is, I was simply pointing out a simple error. No need to make a big deal out of it :S

All 2U, 3U and 4U exams?

lol, my Physics teacher said in final year of university he did 4 nights study. He didn't attend any lectures at all during the year, he was jamming with a band in another country... obviously he was good at cramming. So yes it is possible.

For someone offering English tutoring, I think it's a point worth noting.

Learn to spell the guy's name, it's "Coroneos".

Yes

I asked my teacher today what he thought of the exam... he said it was "strange". hehehe :P

True, but some require integration by parts. I think our school (well, now my old school) is upto Polynomials and is quite close to finishing it.

Hey guys, I need some second thoughts on this. Is it in the syllabus? Most textbooks have it, but I don't think it is in the syllabus. Thanks

Hmm, then someone could potentially lie about their ATAR to get Dux o.O ?

2008 Good school? You mean selective school? Do you honestly think that a selective school would've let students attaining 20-30% in MX2 assessments continue? :P The school ranks around 60th each year. Although, we do have a really good maths teacher, which probably did help with marks.

or more briefly, Using \ cos2 \theta = 1-2sin^2 \theta , \\ cos135^{\circ} = 1-2sin^2 67^{\circ} \\ \frac{-1}{\sqrt{2}} = 1-2sin^2 67^{\circ} \\ sin^2 67^{\circ} = \frac{1}{2} (1+\frac{1}{\sqrt{2}})} \\ Now \ as \ sin 67^{\circ} > 0 , \ sin67^{\circ} = \sqrt{\frac{1}{2} (1+\frac{1}{\sqrt{2}})}}

Hmm, then how do they determine the dux? At my school they seem to know the dux straight away (highest ATAR achiever).

At the top of my head... Example: If z=cosθ+isinθ Prove that: \frac{2}{1+z}=1-itan\frac{\theta}{2} May as well post a solution: Now z=\frac{2}{1+cos\theta+isin\theta} \frac{(1+cos \theta )-isin\theta}{(1+cos \theta )-isin \theta } \\ =...

Reckon it would be possible for him to get 95? Thanks again.