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SAM was 0.4 too generous to me

Then by definition that will be classified as a bad school

Follow your own pace...

It will not 'click' automatically... you will have to think about it to make it click. I always tried to reduce everything in the course to a few rules of thumb/principles that I am comfortable with. To do well in chem (and many other subjects) you have to condition your brain to think in...

You don't need any additional assumptions. ACD = CBE + BEC (exterior angle = sum of interior angles) BEC = EBA + BAC (same reason) now note that CBE = EBA, subtract the second equation from the first. ACD - BEC = BEC - BAC ACD + BAC = 2BEC moral of the story: Don't dismiss...

Don't recycle questions, if you are looking for questions, try to generalise the results of some questions - for example if a question ask you about some arrangement involving 8 Bears and 10 Grasshoppers, try to solve it for B bears and G grasshoppers. I strongly recommend visiting this forum...

but make sure you have enough sleep.. coz you will have to save up to allow you to overdraft sleep time the night before exams

in the top range of marks, the value of marks increases. For example.. In General the difference between a 94 and a 93 is MORE than the difference between a 84 and 83

You're not getting enough sleep if that happens... the only way you can help this is actually sleep..

If you don't get 75+ in your extension 1 school papers, extension 2 would be quite ... say... challenging.

oh anyway. standard form.. you mean.. tan(3x) = {3sin(x) - 4[sin(x)]^3 } / {4[cos(x)]^3 - 3cos(x) } divide numerator and denominator by cos(x)^3.. to save writing, C= cos(x), S = sin(x) T = tan(x) = [ 3T/C^2 - 4T^3 ] / [4 - 3/C^2] now remember 1/C^2 = sec(x) ^ 2 = tan(x)^2 + 1 =...

Hmm..... you made a mistake.. cos(4t) = 8[cos(t)]^4 - 8[cos(t)]^2 + 1

me still trying to figure out where the cosine rule fits in. mean while acosA = bcosB a/sinA = b/sinB dividing first by second, sinAcosA = sinBcosB 2sinAcosA = 2sinBcosB sin2A = sin2B sin2A - sin2B = 0 notice that 2A = (A+B) + (A-B) and 2B = (A+B) - (A-B) so: 2sin(A-B)cos(A+B) = 0...

You should be aiming to get a natural feel for the question. Things to look for are similarities and symmetries.

odds are not good. [17*9!] / [ 2^21]

59 isn't bad... majority of my class last year got something around 40..

calculators are bad graphic calculators are evil

Come on this board and the 4U board frequently and try to answer questions(questions which come on here are usually hard) before us 03'ers. Explain things to others, comment others' solutions. This allows you to see different methods to approach the same problem and also tests your...

Hmm.<!-- let the square be ABCD and the grasshopper be at A initially. let G1={A,C} and G2={B,D}. The grasshopper's position must alternate between G1 and G2, so.. it could only be at A (in G1) after a even number of jumps.. and 9 is not even. so it must be at B or D after 9 moves. after 1...

nope.. that's way too small..