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Nah haha we haven't done that yet. That's interesting though; I naturally doubt that it would come from CM&M, as it was in a PoM test and is concerned with the naming of Haloalkanes. Either I'm wrong and it is part of CM&M, or your book has a typo (which I also naturally doubt)

https://imgur.com/rVbvxpi My teacher says that for haloalkanes, we should number the carbons so that the first alphabetical halogen (in this case, bromine) has priority, rather than numbering them in a way so that the all of the halogens have equal priority in the numbering process. However...

Are you sure that the function isn't (1 - x^2)/(1 + x^2)? The function you wrote has no points of inflection, and the function I wrote has the correct points of inflection.

I think it's just taking me a while to understand it lol...I'm confident that I understand it better now which is good, so thanks for your help :headbang:

I was simply saying that he will predict that the woman experiences the events as not simultaneous. From his perspective, the light from the front of the train will reach her before the light from the back of the train. However, logic tells me (and Excel HSC Physics) that the woman's perspective...

Let me ask something else: In the train video near the top of this page, we see that in the reference frame of the man on the platform: 1. The events are simultaneous for the man 2. The events are NOT simultaneous for the woman. However, is it also true that in the reference frame of the woman...

Let me confirm my suspicions: if the matches were external, ie if they were 'lighting strikes' that struck the ends of the train, than M would see them NOT simultaneously but S would. Is that right?

Ah that makes sense. It seems that solving questions like this is probably easiest when you consider the frame of reference that contains the strikes/lightning/flashes to be the stationary one

But at that specific moment when the strikes occur, when M is opposite S, won't they reach S at an equal time? The strikes are meant to be instantaneous events: I understand that as the train moves to the right that PS is less than PQ, but at the moment of the strikes won't PS=PQ?

Thanks for the help; I can understand that M sees them as simultaneous but could you (or anyone) explain in greater depth why S sees P before Q? I would have thought that t = d/c, and as c is constant, and distance PS = distance SQ, that the time for the light to reach S would be equal, thus S...

My physics teacher gave our class a past paper which included a question concerning simultaneity. He said that the question was actually wrong: https://imgur.com/6dtHN7w He said that to M, the strikes would NOT be simultaneous, but that M would see the strike from Q before the one from P. I...

Re: MX2 2015 Integration Marathon Find \int\sqrt{\tan x} \, dx​

Re: HSC 2015 4U Marathon http://imgur.com/FZnq83p

Re: HSC 2015 4U Marathon The y-axis (x=0)

Re: HSC 2015 4U Marathon When you wrote this line: |z|+|z-2i|=|z-4+2i|+|z-2i| Did you deduce that |z| = |z-4+2i| because the distance from (4, -2) to the line y = 2x - 5 is equal to the distance from (0, 0) to the line? Thanks.

Re: HSC 2015 4U Marathon NEXT QUESTION The equation x^3 + 3x^2 - 4x + 5 = 0 has roots A, B, Y. Evaluate A^3 + B^3 + Y^3

Re: HSC 2015 4U Marathon Oh my goodness, I'm stupid. Yes, I made the mistake that it was from (0,-2) not (0,2)

Re: HSC 2015 4U Marathon Here's my go: √(x^2 + y^2) = √[(x-4)^2 + (y+2)^2] Simplification gives: y = 2x - 5 |z| + |z - 2i| => |2z - 2i| = 2|z - i| (triangle inequality) Clearly, equality is reached when x = 0 Sub x=0 into y = 2x - 5 = 2*0 - 5 = -5. |-5| + |-5i+2i| = |-5| + |-3i| = 5 + 3 = 8...

Re: HSC 2015 4U Marathon I have got as far as saying that tanx - sinx + cosx = 1, but don't really know where to go from there

Oh of course, how silly of me to miss that