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thats fine that wouldn't be Q6 or 7 standard. However comparing coefficients and what not really throws me off.

like we did in 09, im screwed.

You assumed X>0. Unless it states x>0 you cant assume root x^2 is X

No thats right. Expect you might be able to simply it more if you want.

115/120 judging by solutions posted.

Ahahaha, yeh it scared me as well , but i looked over the question and the answer i posted is correct :S enjoy your smoke :D

I done the exact same mistake in the exam. Expect i corrected my self when i was looking back during checking time.

Yep i got that in the exam.

4 e) y\leq 4&space;-x^{2} And y\geq \left | X \right |-2

i just said 2 radians. :S

Because theres a stationary point on F(x) at 1. Stationary point on F(X) at 1 means that F(dash)(X) is 0 at that point.

me :D but massive cbf right now.

I meant your point at 3 , its meant to be a stationary point, so it woud'nt be v-shaped.

Correct , but it isn't pointed however. Its more curvy.

Concavity of F(x) not f, dash (x)

Nope a point of inflexion for F(x), and in turn a stationary point for Dy/dx. - and you dont know if its a inflexion point for dy/dx Its not meant not be Vshaped:S

Intergrate both ,find how many L each tap produced , and find the difference? WHY? They give you the difference for a reason so when you integrate the diffrence in flow, you will get the liters.

Yes along the same lines. but is your point at 3 meant to be V shaped?

Too much work for two marks.

All you needed to do was sub in a value.