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Well, for me it depends on the paper it self. eg 2007 was pretty easy paper, really even question 7 was easy =] scored approx 94% or 95% Others I've managed to maintain a average of 90% Depending on the paper really, some of the question 7 and even 6 where hard and coudn't even attempt...

yeap your correct xD here ill post up some level 2 questions, people posting too many simple question. Q] Let P(x) be a polynomial give by P(x)= ax^4+bx^3+cx^2+dx+e Suppose the remainder is px+q when P(x) is divided by x^2-m^2 i) show that p= 1/2m *{P(m)-P(-m)} and q=1/2 *{...

anybody can teach themself 4unit. dont listen to the crap that people say you can't or you woould fail. just try it =]

Hi, can you help me out by posting up the solutions to the multiple choice answers of the 2007 paper, I know its located in the website but for some reason I can seem to access it =[ Thanks PS: This thread can also be used for any other questions relating the 2007 paper.

No girls stay away from this theory, it sucks.

you got me wrong, I love your ass hole.. can i fuck that with your consent =]

I feel honoured =] Call me, tonight =]

hey let me cum on your face, and then you will understand the whole cumming on her face thing.

I prefer the face followed up by a golden shower.

I dont know how, can you give me some pointers or tips. Thanks

"why" Thats a good question, I guess we will never know =[

It doesn't look good buddy. Call up tafe asap.

its freaking waste of time going to school anymore. we dont do crap, all we do is sit down and past papers =[ maths and english are fun.. but the rest BORING ={

People go to high ranking school suck at having a social life..

hey yeap thats the correct answer.. you need to state that the remainder was ax+b and that you had to write it in this form P(x) = (x-2)(x+5)Q(x)+ax+b then go on to get two equations... and then find your a and b and then thats your remainder.. its not a 4 UNIT quesiton its just a...

man where is the jobs at myers.. stuff sydney cant find a single job lol I've applied through a thousand job and still no call back.. com'on is it just my luck.. stuff sydney and the jobs..

Use Newtons method to find a second approximation to the positive root of x - 2sinx = 1. Use x=1.7 as the first approximation x(new)= 1.7 - ( 1.7-2sin(1.7)-1)/(1.7-2cos(1.7)) x(new) = 2.3 keeping in mind to use rad in your cal new question When a poly is divided by (x-2) the...

that question wasn't really hard, just need to imagine how it turns out to be.. but seriously not enough time, that was the thing about it.

hey that was in my trial paper.. you need to use a sector of two circles. xD