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mhm, dw guys i got it now :) TY all. I got ONE MORE question related to this so pls help (a) Differentiate from first principle y = x^3 3x^2 (b) Find the gradient of the secant though the points A and B on this curve, where x=1 and x=3 respectively. ? Thanks

Find the equation of the tangent to the curve at the point A 2x - y + 1 =0 I guess the gradient of the tangent here is 2? Therefore the gradient of the normal is given by the perpendicular line properties? m1 x m2 = -1? Is the gradient of the normal -1/2?

Soz, but i'm a bit confused here..

w8 then what am i doing wrong here? e) y-11= -1/4 (x-3) y-11= -1/4x + 3/4 y= -1/4x + 47/4 ? Answer: x + 6y = 69

Do i flip the gradient? m=4 into m=-1/4? soz if this is dumb...

littlehelp? Differentiate from first principle y = x^2 +2 =2x Find the gradient of the secant through the points A (1,3) and B (3,11) on this curve. =4 Find the equation of the tangent to the curve at the point A 2x - y + 1 =0 Where does the tangent cut the x-axis x = -1/2 Find the...

thx Meno :). One more question related to this. Find dy/dx if y= a^2 + b^3 + c isn't supposed to be 2a + 3b^2? The answer is 0?

1/√x+2 + √x+2 1/2√x+2 Thanks man :)

mhm, ye :)

this? 1/√(x+0)+2 +Vx+2 ?

Differentiate f(x) = √x+2 from first principle. Ok, here is what I got at the end... 1/h x h/√(x+h)+2 + √x+2 The answer is 1/2√x+2 . But how? Thanks.

mhm, thx man, i though that was a 1 at the end ==''. Just want to check somethin A small car of mass 800kg moves from a stationary position to a speed of 60km/h in 10 seconds. (a) Calculate the average acceleration of the car. is it.....? 60-0/3.6x10 = 1.67m/s^2? Do i ignore the 800kg?

bump, thanks man, appreciate it :). Just wanna ask another question: A student is using a luxmeter to measure the intensity of light at various distances from a light source. At distance, d, the intensity is measured as 1 units. If the distance is reduced to d/2 the intensity would be closest...

littlehelp? If electricty cost 15c per kilowatt-hour calculate i) The energy consumed ii) cost of using: a) 2000W radiator for 6 hours b) a 100W globe and a 1kW radiator for 3 hours c) a 7200W water heater for 15 mins thanks :)

uh 755 according to this http://www.smh.com.au/nsw/my-school-secondary-2012. what do you think?

Sorry if this is a dumb question =='' but.... Does the HSC assessments (especially English) change every year? I saw the English assessments task that people did in my school for their HSC and I was wondering If I would get the same thing next year (I'm Yr 11 btw). I will be doing the same...

ye I checked, that's right man thx appreciate it :). I have my yearlies coming up so i might ask a lot of questions... The gradient of the normal to the curve y= a/x + b at the point (3,-5) is 3. Calculate the values of a and b. I was wondering if this is how you do it...: y=a/-3 + b = -5...

thx man but was that meant to say -540≤θ≤540? Bumping this since i need help with another question related to: Tangents and Normals If the slopes of the tangents to the curve y= ax^2 + bx + c are 4 and -14 at the points (1,5) and (-2,20) respectively, find a, b and c. Thanks :)

Littlehelp? Solve for -180≤θ≤180, round you answers to the nearest degree? √3 tan3θ + 1 = 0 THX

i type my notes up on word. Normally I would go to the resources section and open up notes for the same module, and try and combine all "relevant" stuff in for each dot-point. Then rearrange it into my own words. Is this like..a good way for making notes?