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Are you sure the speed is 20% of v? Cause if answer is 50m, then ball travel 25m after rebounding of board. Plug that into cartesian and youll get smthing like v=sqrt8 At least for me.

Find the speed and direction of a particle which , when projected form a point 15m above the horizontal ground, just clears the top of a wall 26.25 m and 30m away.

Sorry still no clue. Testing 1/w was a root was part a of the question. So...

I think its +-y = +- x +1 therefore it will be interesection at y=1 of 4 lines

Sorry shaon0, could you just expand on how to confirm 1/w. Im thinking to do that question w^8 =1. But w is not a root of unity, but a root of p(z). nd thxs for the roots bit. Ive got that.

any1?

Thanks very much!

For this one, what do we do from here? sorry for idiocy.

Could you expand on that?

What about for this particular case?

How do u know w^8 =1?

Also i have 1 more question Given at t=0 x=0, t=11 x=0.5, t=18 x=0 Find x at t=7, 9 Assuming particle moves in straight line with a) unifrom acceleration b) SHM with period of 12 seconds

For SHM say this Q A particle executes SHM with n =pi/4 a =10 Find v and aceleration at x=6 When finding v v^2 = (pi/4)^2(64) How do we take the sign from here on? Also for max acceleration i argued that it occurs at x=0 but acceleration then = -3pi^2/8 So what reasoning is used to say...

well if y is a root then p(y)=0

cause if ab = y and aby = -q then y^2=-q

And also prove that if w is a root of P(z) = z^8-5/2z^4+1 then 1/w is also a root Also find one of the roots of P(z)=0 in exact form

What about this: Find the conditions for the roots of the cubic equation ax^3 + bx^2 +cx + d = 0 to be in geometric sequence

If w is a compelx cube root of 1, form a cubic with root (a+b)^-1, (aw+b)^-1, (aw^2 + b)^-1

Solve the differential equation a (d2x/dt2) + 16x = 0 (SHM) Also, when solving strait line motion equations. How do we take the signs. For example A particle moves in a straight line so that at any time t, its displacement from a fixed origin is x and its velocity is v. If acceleration is...

Parabola x=2at, y=at^2 has parameters p, q etc.. M is mid point of chord PQ, T is point on parrabola where tangent is parrallel to PQ and I is point where the tangents at P and Q intersect M,T,I lie on a vertical line, with T the mid point of MI The tangent at T bisects tangents PI and QI What...