The domain is all the x coodinates except the ones where you can't square root a negative number. For 1., 9-6x>=0, x<=3/2
The range is all the possible y coodinates. This case, it's y>=0. You can get this from sketching the graph
LHS= (k+2)(k+3)...(2(k+1)-1)(2k+2)
=(k+2)...(2k+1)(2k+2)
=2^n [1*3*...(2k-1)] * (2k+1)(2k+2)/ (k+1)
=2^(n+1) [1*3*...(2k+1)]
=RHS(cbb doing this part, but it's really simple)
Line 3. It's all over k+1 because the expression for n=k+1 doesnt begin with k+1, but the assumption uses the...
BOS(board) hasn't published this process in a pdf from what I know. Though data analysis and statistics will definitely be involved in this process.
@OP If you manage to come first in your ranks, 99.95 is definitely possible. This makes me wonder if it's better to go a high ranked school...
|zero| is right. Though technically they do some data stuff for the students that aren't ranked 1st. They do this by looking at the internal mark differences, the mean, standard deviation and all that statistics shit