just to make it more readable x).
(1+sinx+icosx)/(1+sinx-icosx) = sinx + icosx
DEDUCE that
(1+sin pi/5 + icos pi/5)^5 + i(1 + sin pi/5 - i cos pi/5) = 0
I have to prove that LHS = RHS right, but am i allowed to divide the whole equation by (1 + sin pi/5 - i cos pi/5)
so i get (sin pi/5...
My question states
(1+sinx+icosx)/(1+sinx-icosx) = sinx + icosx
DEDUCE that
(1+sin pi/5 + icos pi/5)^5 + i(1 + sin pi/5 - i cos pi/5) = 0
I have to prove that LHS = RHS right, but am i allowed to divide the whole equation by (1 + sin pi/5 - i cos pi/5)
so i get (sin pi/5 + icos pi/5)^5 +...
Excercise 2.2
if p is real and -2< p <2, show that the roots of the equation x^2 + px + 1 = 0 are non real complex numbers with a modulus of 1.
Yes I've checked the worked solutions xP... doesn't seem to explain the 2nd part of the question..
I thought in a typical 3 mark induction question
you'd usually get 1 mark for the initial process of the n = k+1 and simplifying
another for substituting or using the assumption...
and a 3rd mark for justifying the statement for n = k+1...
so all 3 marks are allocated in part 3...? though u...
Could anyone send me a copy if its online..?
Anyone willing to send a scan to me?
ijuinenzan@hotmail.com is my email btw :).
if your bothered to go that far... thanks!
Is there a correct, short generic way to conclude MI...? It seems my teachers are always picky on what you write as a conclusion in ur mi statements... ><"... whats a satisfying enough conclusion that most teachers will accept?
Well the title states all, what exactly is a band? Is it the same as the school certificate where a post scaled mark of 90+ = band 6, 80-89 = band 5, 70-79 = band 4 and ect...? or is it a different system?
>_>"
Lol. I did this question for my mate a while ago and i handed him the solution but now and he lost it... & I can't remember how to do it.. could someone post up the solution... noting Q is at (0,-ap^2) for simplification.
haha mines next week... xD
i was gonna go as Kuran Kuname not that anyone knows who that is anyway xD... $150 for 4 events isnt that costy... xD thats like averaging $37 ea
Theres also a pretty tricky method solving by general solutions for stuff like sin 9A = cos4A or similar stuff xD...
but i can't be bothered going into that xD