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Thanks Pal!

How would i integrate dx/(2x+5)^4

Omg man thanks so much i fully understand it now have a nice day

how about cos(-150)

How would i find the exact value of cos(-225) and Sin(315), can you please show me how you got to it, i used to know this but when i was revising i was completely lost.

may i have a sample on chemistry notes please before i buy.

1)i)Given A,B and C are angles of a triangle and: TanA/5 = TanB/6 = TanC/7 = k, show that k= Square-root of 3/35 ii) Hence calculate the smallest of the angles to the nearest minute. I'm kind of lost in this question, any help would be great thanks!

yea i dont understand what the n-th term means.. someone told me it means anyterm but i still dont get it

Really? just 7n? what does 7n mean

Find the nth term of the arithmetic sequence 7,14,21,28 Dosent tell me what term to find so i don't know what to do.

y=x^2-6x+8 Factor and sketch the quadratic. Hence find the range of each function (i) with unrestricted domain. (ii) with domain x is greater than or equal to 5, (iii) with domain 0 is less than or equal x which is less than or equal to 5. Any help would be appreciated

Given two roots of 2x^3 -kx^2+8=0 are equal, find k. Need help on this question so hard.

If alpha and beta are the roots of x^2 - 5x -5 = 0 find a^2+b^2, a^3+b^3 Is there a way i can manipulate the question to solve it or is there a rule that i must follow.

you couldve got rid of the squart by multiplying it by 1 - sqrt(3), i thought when trying to get rid of the root your suppose to times it by the denominator

why arent u suppose to simplify the denominator?

I got lost when you times it by 1+ Rt 3 for both sides arent you suppose to times it by 1- rt 3 on both sides? and what did you do for the result to get it into -2 -rt 3 form

when i expand i get 1+ rt3 over 1-1x rt3 dont know what to do next

im stuck on this problem because the answer i get isnt what its suppose to be Evaluate: tan45 + tan60 over 1-tan45 x tan60

Oh i realized my mistake now thanks ;)

thanks i get it now :) How about 5s-3t-13=0 3s-7t-13=0 elimination method