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Re: HSC 2013 4U Marathon 1. As the 'show area of triangle produced by tangent to hyperbola and asymptotes is constant,' but in this case just the rectangular hyperbola y = A/x. We had (f(x)-xf'(x))^2 * 1/f'(x) = const., differentiating we get f(x) = -xf'(x) and then ln(f(x)) = -lnx + C =>...

Re: HSC 2013 4U Marathon (1) (x^2 - y^2)^2 >= 0 (2) 2(xy - 2)^2 >= 0 Add (1) and (2)

Well, just spend 40 mins getting q8 out, christ. Awesome paper, thanks.