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Re: MX2 Integration Marathon Use the substitution u^2=x+1 to give you ln(x+1)+c

would it be possible to have the option of doing both the ext 1 and ext 2 on the same day? also is there any free parking near the library?

would love to do it but parramatta is so far away from me

94-5

yeh memorize definitely

Re: HSC 2013 4U Marathon Does anyone have any 2013 papers?

school rank?

Re: MX2 Integration Marathon When your integrating you cant use that rule twice, as it will always lead you to having a positive integral on both sides, meaning youre just solving 0=0, so i think somewhere you made a mistake in which it shouldn't go to 2I, but rather go to 0 on the lhs

Re: MX2 Integration Marathon For i, -times both sides by cosec^2x -use the substitution u=cotx -Use partial fractions for ii, use standard integral arctanx to get pi/4

integrate from ln(34e^5/1561) to ln(2e^5) 2dx/(5-x)(46.5-ln(5-x)) woops answer results in 2ln79.90, does that matter?

Re: MX2 Integration Marathon -pi/ab?

bump

bump

Eng Adv 8/160 Economics 6/80 MX1 2/65 MX2 2/25 SOR II 1/15 School Rank: 2012:80 2011:76 2010:67

Re: MX2 Integration Marathon 2nd part of second line is wrong should be 2x^2cos(x^2)

Re: MX2 Integration Marathon integrate sin(x^2)

Re: MX2 Integration Marathon use double angle formula for cosx

^i think it means sydney grammar

Make it 587400 x (1.005^(n))-346095 x (1.005^(n)) = 587400 Then factorise out the 1.005^n, and divide both sides of the equation

Wow 2 100's, what is your school rank like?