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Structure according to texts, works much better than themes. Quotes usually sound pretentious - if you want to, you can, but you better back it up with an intelligent response

2-3 hours is enough, as long as you're doing QUALITY study :/

I don't believe ACER is known for divulging their secrets.. I think all you can get is from their website ACER | CSTP - Overview

He's referring to the Einstein ATAR calculator which gives (I presume) an ATAR that corresponds with the relevant mark according to statistics given by students and the Board of Studies. :/

And are going to end up going to Harvard... ><

Depends on how confident you are in your maths - if you can grip the concepts well it should be about a 5/10 at most. If you don't.. well it would take a lot more work to mitigate the pain it can bring to those who don't understand everything, and in that case it would be up to 10/10 (it is...

Work at school and you won't need to work as hard at home :)

Yeah, it'll work for the sciences.

By the way, if you do want to learn the electron configurations for larger elements, look up Pauli's Exclusion Principle.

Calculus. That is all you need to know. Oh and some other random number concepts related to probability and complex numbers.

98-99+ so far, as long as you get band E4 or 6 in everything.

For a), determine the equations for displacement against time for the two particles and the equation for velocity against displacement, then add them together and equate the new equation to 180 metres. For b), substitute 90 metres into your equations. Hopefully that should work :/

Why is the gradient of the curve in units? :/

A couple of scrawls in my class textbook :)

Generally, transition metals have a valency of 2+. Don't assume it's true for all metals though, because if they give you something like copper (IV) chloride then the copper has a valency of 4+. In terms of electron configurations, all you have to know are the first 20 elements. After that...

Hurstville

Just substitute the values nCr, nCr+1, nCr+2, nCr+3 into both sides of the equation and it should come out fine. It takes less lines that it would seem too!

Integrate with complex numbers. :)

Sub 1/w in the equation, then take (1/w)^8 out of it, then you get the original equation, which is equal to 0. Hence, 1/w is a root. \because P(w)=w^{8}-\frac{5}{2}w^{4}+1=0 \therefore P(\frac{1}{w})=(\frac{1}{w})^{8}-\frac{5}{2}(\frac{1}{w})^{4}+1...

Integration < Graphs < Volumes < Mechanics < Conics < Complex < Polynomials < Harder 3U (doesn't really count) Disliking polynomials because I never did any work for it... >.< (the complex polynomial work, that is)