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Torque= radius x force =(3i -2j) x (5i + 7j) =21k - (-10)k =31k

BIOL1001: Topics covered in lectures and practicals include: introductory cell biology, with particular emphasis on how cells obtain and use energy; the diversity and biology of microorganisms; an introduction to molecular biology through the role of DNA in protein synthesis, including current...

I did human biology without doing the recommended bridging course. I did get a credit, but I can't say I ever really understood any of it. I think I passed with dumb luck. Hope that helps.

EDIT: this is from a mechanical perspective. Actually, of all the universities, Sydney uni engineering tends to be theoretical not practical. There's lots of maths and classical mechanics classes and not too many practical ones. However, in first year there might be one or at most two classes...

No you don't. Radians are dimensionless. 2 is just a number; no need to bother writing "rad" or anything like that.

The radius of the cylinder is the x value at C. since y = x^2, then at y=h, x = sqrt(h). The volume of the cylinder is the pi*radius^2*height = pi*sqrt(h)^2*h. Put that under the volume of the paraboloid in pt i and you get half.

But their best song this year, Sprawl II, didn't.

If you want to do maths, go for it. Don't choose your second course preference just because your friend thinks his university is more "prestigious". (That's BS anyway; UNSW is highly regarded when it comes to the sciences.)

Is there a list for what subjects the numbers represent? EDIT: Found one http://www.uac.edu.au/documents/international/HSCcourses.pdf

Overall mark I believe. I got a 98 external last year as well but my 92 internal dragged it down

The 16th in the SMH and probably the DT too

http://boredofstudies.org/view.php?course=1

I thought angle-sum was 3 unit.

You posted that at 1 a.m.? Nice. Try this (there should be a dx in the 2nd line)

(I'll use ' instead of the usual dots)<o></o> <o></o> x''=0 (1a)<o></o> x'=Vcosθ (1b)<o></o> x=Vtcosθ (1c)<o></o> <o></o> and<o></o> <o></o> y''=-g (2a)<o></o> y'=Vsinθ -gt (2b)<o></o> y=Vtsinθ -½gt²(2c)<o></o> Find the max height<o></o> y'=0 =>...

Re: Also Range question :S For the range question. y=-(x-6)(x-1) From the graph it's evident the lowest value of y is -6 at x=0 and x=7, and the highest value of y is at the vertex, x=7/2 f(7/2)=-(7/2-6)(7/2-1) =25/4 Therefore range: -6≤y≤25/4

Re: Also Range question :S The square root has to be ≥ 0 Therefore x^2 - x - 2 ≥ 0 (x-2)(x+1)≥0 x≥2; x≤-1 That's the domain.

I can! But in all seriousness, I enjoyed reading that. Thank you. BTW You mentioned marking criteria. Do English teachers have a specific marking criteria we don't see, or do they just use the very general three dot points you see on the back of study guides?

That's a graph of the HSC mark (x-axis) vs scaled mark (y-axis). The red curve's general maths, and the green curve's advanced English. The blue curve's Ext 2 maths, which I threw in there for comparision (one of the highest scaled subjects). So an 80 in gernal maths isn't too far off an 80...

My maths teacher once told me the axes of Decartes' original plane wasn't at 90 degrees.