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sin(A)cos(A)sin(2A)=\frac{1-cos(2A)}{4}\\ RHS: \frac{1-(1-2sin^2(2A))}{4}\\ =\frac{2sin^2(2A)}{4}\\ =\frac{sin^2(2A)}{2}\\ =\frac{(2sin(A)cos(A))(2sin(A)cos(A))}{2}\\ =2sin^2(A)cos^2(A)\\ =(sin(A)cos(A))(2sin(A)cos(A))\\ =sin(A)cos(A)sin(2A)\\ =LHS\\ therefore true

SOOOOO SMART!!! I forgot about that method.... Thanks sooo much... for your help, I shall remind of how to use LaTeX. type [.tex] before what you want and [./tex] after what you want (without the full stops) well, that's what I got taught anywyay... Thanks so much cya

Hi guys, just preparing for my maths 3U test on Friday and came across some questions I didn't quite get. Could you please advise me on how I would go about answering {exact value} : sin(2tan^{-1}\frac{1}{2}) btw the answer is 4/5 but I don't know the process of getting to that answer...

Some of them are extremely unorganised and unhelpful some of the time. Or, you might want a more personal experience to work on your own weaknesses.

Re: James Ruse Year 11 Term 4 Extension II 2007 paper - complex (open me, paper inclu Thanks sooo much. I can view it, so i guess it has not errored... Thanks again :D

Re: James Ruse Year 11 Term 4 Extension II 2007 paper - complex (open me, paper inclu Problem is, I wont really know if I have any problems until I can mark my solutions and see what I got wrong. If I do get any problems as I am doing it, I shall take your advice, however until then, if anyone...

Hi guys, was just wondering if any of you have the solutions to this paper, I don't seem to have it. This would be much appreciated thanks

Yeh I am doing this also except I got a Uni student for a long lesson a week to help me along (i.e. keep my pace and explain the concepts) and I use this motivation to write my notes so I don't have to do them later (just the investigations/pracs left out) and I think this way is better since it...

Hi guys... Could you help me out in trying to understand a question from conquering chemistry, chapter 5, question 20? I think I know how to get the concentration of the dilute solution (I get around 0.159856... mol/L). I do not understand how to find the initial concentration of the...

Thanks guys so much... That was very useful :d

Hi guys, I need help understanding the solution to a question. This was a former HSC question, I don't understand one aspect of the solutions. QUestion: If y=10^x, find y' when x=1 Answers: y=10^x\therefore lny=xln10\\\frac{d}{dx}(lny)=\frac{d}{dx}(x ln 10)\\\mathbf{\frac{1}{y}...

Also, what about for a sydney boy's paper? Thanks :D

Hi I was just wondering... what a good mark in a past Task 1 James Ruse 4U paper would be. I am doing some past papers for my first HSC task in two weeks and was wondering what would be an average mark for someone in a school ranked around 10-15. Thanks :D

cool it worked, sorry was just trying it out!!! THANKS

0=\frac{4x^{2}+3x}{4x*7y^4}

cool. Thanks once again... I am going to have some fun on this... cya

hahaha, well that message may be passed on to SpiralFlex then. also btw, how do you write with proper mathmatical symbols and everything on the forum? I was writing it up on word and was going to put up a photo of that. Thanks once again.

hahah By the time it took me to write up my solutions, I already got them THANKS... I just realised that i was missing the very last step of multiplying the top and bottom by SQRT(2) just a question but isnt it better to leave it in the form that its in in the second last line? THANKS AGAIN...

From the Arnold/Cambridge 4U book. Exercise 2.1 question 9b. It says solve the following quadratic equation: 2x^2 - 4x + 3 = 0 I keep getting 1 (+-) [i SQRT(2)]/2 but the answer is 1 (+_) i/[SQRT(2)] and I dont know how to get that Help is much appreciated :D Thanks

already got it, yeh, well, at least paying the money will make me concentrate on it more... hopefully :D