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Need help to find the equation of the directrix and the coordinates of the focus. (a) Sketch y= x²+2x-8, showing intercepts and the minimum point. (b) Find the coordinates of the focus and the equation of the directrix of the parabola. Part a done, giving (-1, -9) as the minimum which is...

- Let the point P be (x,y). - Then find perpendicular distance for each line. - After finding perpendicular distance, equate them and simplify.

The latus rectum of a parabola has endpoints (-2, 3) and (6, 3). Find two possible equations for the parabola. All I've done is found the equation of the latus rectum, which is y = 3. I'm not sure what to do next. Answers are: x²-4x-8y+12= 0 and x²-4x+8y-36= 0

It's crap and not worth your time & money.

Very true, my friend was "privately" tutored for 2U/3U maths for the private class rate of $50. A "private class" of 30 students. Now they've arranged another private class for him which only has 2 students. But he's paying $100 for it, being taught by a Uni student who only graduated last year...