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yes

probability without even close competition. followed by inequalities

this is the method i use for pretty much all inequals like this

there is that stuff but it's not in the exams i feel ya man, i'm not lookin for med either (mainly because i don't want it at all), mx2 is my life as well :P i'm going to do electrical next year and i did enjoy engineering studies a lot.

i do remember being a little stumped when i did the exam

well for me, my other subs are good enough to get the atar i want and i'm glad i did the subject because it is extremely interesting. but hands down you're right, the subject is ridiculously difficult for what you actually get out of it

when i did this question i was unaware it was a theorem but instead explain that it is parallel because the midpoints will be vertically half way between the ends of the intercepts...

we were taught to do this in class but it's slower than just comparing the coefficients

that's not a partial fractions Q, you can just do common denominators. i was obviously referring to "Find integers A & B such that..."

the aligned mark is published in results. you can however pay to get your raw back.

it's the best feeling tho

it's D. the line in the center of the hole in B indicates it's two separate pieces?

because it took a while?

what? i said it's D but i put B in the exam?

it's interesting and has great aligning, but the scaling is poor and it's extremely difficult. the exam is nearly all skills and application of knowledge, very little content (which i like a lot but it makes it hard, so i wouldn't recommend it if you are looking for a nice atar). i'm glad i did...

mistake

ahh now i get what you're saying. ffs that's such a stupid mistake

moments from center of mass

the F in part i is overcoming the weight.

BC = (22.5*7.5 - 30*3.75)/3.75 (assumed compression)