2026 HSC CHAT (2 Viewers)

[NotBamboo]

@Shavi Masee
got it with the help of AI cus i forget about turning point silly me
View attachment 47383
AND CHECKING WITH DESMOS DRUMROLL PLEASE
View attachment 47384

@cheesynooby
can u teach me how to use the element of symbol for domain and range thanks

if anyone is still confused why i used differentiation i found smthing for u

in the working out i replaced f'(x) with 0 for the stationary point (that was the word i was looking for)

@cheesynooby is there a better way to solve it that doesn't include derivatives (for shavi to understand)

 

[jane1820]

if anyone is still confused why i used differentiation i found smthing for u
View attachment 47391
in the working out i replaced f'(x) with 0 for the stationary point (that was the word i was looking for)

@cheesynooby is there a better way to solve it that doesn't include derivatives (for shavi to understand)

Why r u over complicating stuff omg
here ill send my own working

 

[jane1820]

@Shavi Masee @NotBamboo

 

[NotBamboo]

@Shavi Masee @NotBamboo View attachment 47392View attachment 47393View attachment 47394

appreciate it
yeah, actually doing the inequalities was better than randomly testing and graphing points
also what is this 'sub in any random number from' u couldve phrased it any other way like 'test... neg number, pos number'

whered u spawn in the desmos graph from
your range; (-infinity, 0.5) does not look right, the graph does not ever touch y=0
i can sub in 0.6 and get still an answer so ur max is wrong too silly

 

[jane1820]

appreciate it
yeah, actually doing the inequalities was better than randomly testing and graphing points
also what is this 'sub in any random number from' u couldve phrased it any other way like 'test... neg number, pos number'

whered u spawn in the desmos graph from
your range; (-infinity, 0.5) does not look right, the graph does not ever touch y=0
i can sub in 0.6 and get still an answer so ur max is wrong too silly

OMG I DIDNT REALISE MY RANGE ABDASDJIASJDAOJDSIA
i meant (-infinity, 0.7) bc according to the graph thats the highest it goes

also dw abt the phrasing lmao as long as it makes sense

 

[NotBamboo]

@jane1820 @Shavi Masee
ill clean up my working first and make a new thread
this is digressing from the purpose of the thread

 

[NotBamboo]

OMG I DIDNT REALISE MY RANGE ABDASDJIASJDAOJDSIA
i meant (-infinity, 0.7) bc according to the graph thats the highest it goes

also dw abt the phrasing lmao as long as it makes sense

.7 isnt right either silly
u cant rely on desmos for surds u gotta actually do the math

 

[jane1820]

.7 isnt right either silly
u cant rely on desmos for surds u gotta actually do the math

i wasnt taught the math for figuring out range, my teacher said just look at the graph

 

[cristal]

ok so here's my working
so if you draw up x^2 +2x+3 you can see domain is all real x because it never touches 0 and below due to the square root sign so that's domain

onto the range, so just for the quadratic we can see the minimum value/turning point is -1 (just remembered formula is -b/2a whoops). We use the min value bc the smaller the x value the larger the y value for the function.
Using -1 we sub it into the 1/sqrt of x^2 +2x+3 and our maximum value is 0.7071...
as the quadratic HAS to be greater than 0 (bc you can't do 1/0) and also because when doing square root functions you don't get negative (only outputs positive apparently)
range is : 0 < y </ (less than equal to) 0.7071...

(does this make sense or do I need a diagram?)

 

[cristal]

but yh you'd probably just write it as 1/sqrt 2 instead of 0.7071...

 

[cristal]

@Shavi Masee soo do you understand

 

[cristal]

or do I presume your brain's in overdrive mode?

 

[cristal]

Uhhh can't talk?
(I mean you did message on discord soooo)

 

[Shavi Masee]

or do I presume your brain's in overdrive mode?

I will have to sit down with my maths book and go through this
I still overheating
There's like barely any internet here, so it's taking ages to send

 

[NotBamboo]

ok so here's my working
so if you draw up x^2 +2x+3 you can see domain is all real x because it never touches 0 and below due to the square root sign so that's domain

onto the range, so just for the quadratic we can see the minimum value/turning point is -1 (just remembered formula is -b/2a whoops). We use the min value bc the smaller the x value the larger the y value for the function.
Using -1 we sub it into the 1/sqrt of x^2 +2x+3 and our maximum value is 0.7071...
as the quadratic HAS to be greater than 0 (bc you can't do 1/0) and also because when doing square root functions you don't get negative (only outputs positive apparently)
range is : 0 < y </ (less than equal to) 0.7071...

(does this make sense or do I need a diagram?)

GOOD STUFF KRYSTAL IM PROUD OF U <3
yeah heres my full 12 pages of working out that u did in like 5 sentences
Domain & Range help for my bestie | Bored Of Studies

 

[cristal]

GOOD STUFF KRYSTAL IM PROUD OF U <3
yeah heres my full 12 pages of working out that u did in like 5 sentences
Domain & Range help for my bestie | Bored Of Studies

Rare moment of Bamboo showing praise/ emotion

 

[cheesynooby]

@cheesynooby is there a better way to solve it that doesn't include derivatives (for shavi to understand)

I just find the range of the quadratic, then sqrt and reciprocate it
like the quadratic is y ≥ 2
sqrt it so y ≥ sqrt2
and then when u take the recpirocal u get 0 ≤ y ≤ 1/sqrt2

 

[cristal]

GOOD STUFF KRYSTAL IM PROUD OF U <3
yeah heres my full 12 pages of working out that u did in like 5 sentences
Domain & Range help for my bestie | Bored Of Studies

Yh but you showed it more clearly
My one has no diagram to reference (yeah I made one but not much point + didn't use my Wacom so not as neat)

 

[barnyard]

There's like barely any internet here, so it's taking ages to send

is this caves beach!!!!!!!!!!!!!!!!!!!!!

 

[Shavi Masee]

is this caves beach!!!!!!!!!!!!!!!!!!!!!

YESSSS IVE JUST LEFTT

How in the world did you get that lmaoo