cute lil monkey
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75+ for 90+solarised
what do you think cut off will be this year?
60+ for 80+
75+ for 90+solarised
what do you think cut off will be this year?
77-78 raw for b6solarised
what do you think cut off will be this year?
I did that too, I hope they give 2 marks for that instead of just 1If you drew the graph for the Ferris wheel question and got the intersection points from that would they give you the 4 marks?
maybe somewhere in the mid80s to low 90s i reckonHey guys, I sat the math advanced paper yesterday and after looking over the answers, predict I got around 75-80. Any thoughts on what this will scale to my exam mark.
Also they never taught us the identity: If cos(ax+b) = cos(c) then ax+b = c. So I don't understand why some solutions use thatIf you drew the graph for the Ferris wheel question and got the intersection points from that would they give you the 4 marks?
Thank youmaybe somewhere in the mid80s to low 90s i reckon
that's not an identity mate that's common senseAlso they never taught us the identity: If cos(ax+b) = cos(c) then ax+b = c. So I don't understand why some solutions use that
I know if ln(ax+b)=ln(c) ax+b=c and if a^mx+b=a^c then mx+b=c but I didn't know it would apply to trigonometry too cause I never came across any past paper with that type of trigonometric equationthat's not an identity mate that's common sense
not neccessarily true and I don't think that 'identity' is even correct. The cos function has several cycles so the angles aren't neccessarily the same for the eqn that was given... you'd need to prove that the +2npi cases do not contribute...that's not an identity mate that's common sense
exactly you have to think about the cosine and sine functions, also the 2npi cases don't contribute since they lie outside of the first full rotationnot neccessarily true and I don't think that 'identity' is even correct. The cos function has several cycles so the angles aren't neccessarily the same for the eqn that was given... you'd need to prove that the +2npi cases do not contribute...
mb i only saw the 'identity' not the qn yall are talking ab. I lowkey just brute forced using compound angleexactly you have to think about the cosine and sine functions, also the 2npi cases don't contribute since they lie outside of the first full rotation
I don’t see why they wouldn’t give the four marks if you correctly graphed it and got the correct heights. Can anyone change my mindI did that too, I hope they give 2 marks for that instead of just 1
They asked for decimals, which you can't get if you graph it since it wont be completely accurateI don’t see why they wouldn’t give the four marks if you correctly graphed it and got the correct heights. Can anyone change my mind
You find the times where they intersect exactly being 3 and 27 and then sub those in to the equation to get the exact heightsThey asked for decimals, which you can't get if you graph it since it wont be completely accurate
they probs will they have in the pastI don’t see why they wouldn’t give the four marks if you correctly graphed it and got the correct heights. Can anyone change my mind