ruse 3u trial q (iii) (1 Viewer)

[ExtremelyBoredUser]

Theres no sols to this paper so I just wanted to check my response with others. How would u do this q?

 

[mmmmmmmmaaaaaaa]

Part ii) sample standard deviation is sqrt(pq/n)
Part i) I think it’s more so the fact that it becomes much more difficult to calculate with bigger numbers with binomial distribution

 

[ExtremelyBoredUser]

Part ii) sample standard deviation is sqrt(pq/n)
Part i) I think it’s more so the fact that it becomes much more difficult to calculate with bigger numbers with binomial distribution

yea those were straightforward i mean (iii)

 

[jklol]

yea those were straightforward i mean (iii)

are there no worked solutions?

 

[ExtremelyBoredUser]

are there no worked solutions?

no, well at least what i know of

 

[jklol]

what year is this btw? I wanna do it lol

 

[ExtremelyBoredUser]

what year is this btw? I wanna do it lol

2021 ruse paper

 

[yanujw]

I calculated 99.72%. You need to use the complementary probability that none of the sample has sample proportion < 0.22

 

[ExtremelyBoredUser]

I calculated 99.72%. You need to use the complementary probability that none of the sample has sample proportion < 0.22

View attachment 36717

Yep i got the same bro,basically same method


so z score = 1/2 so p(z<1/2) corresponds to that prob

continue with yans working out

Anyone else can confirm?

 

[mmmmmmmmaaaaaaa]

Where did you find it? The paper

 

[ExtremelyBoredUser]

Where did you find it? The paper

I got the pdf from a friend, I can send it to ur pms if u want but i wouldnt recommend it if ur looking for hard qs, 2022 ruse is way better in that regards imo