Mathematics Extension 2 Predictions (3 Viewers)

[MemeCognoscente]

Good luck guys

 

[josh312]

After Q14 im

 

[tgone]

After Q14 im

that was kinda funny lmfao they wrote some nice creative writings

 

[aim for 95+]

So kind for a student who just came here for two years, questions are abstract and see you E4.......

 

[tgone]

So kind for a student who just came here for two years, questions are abstract and see you E4.......

yeah it was like a really abstract test that’s a good way of putting it but for the most part just going through with calculations got to the required result so I think it’s ok- predicting a very low E4 cutoff this year though so don’t be too disappointed

 

[MemeCognoscente]

What do you guys think the E4 cutoff will be?

 

[aim for 95+]

What do you guys think the E4 cutoff will be?

Can I ask you about how many marks you think you got?

 

[sga2]

did anyone know how to do the final part of q.16?

 

[RileyC]

I don't know about other answers for the final of 16, but I know that 1, i and -i worked for a set of number which fit all 3 criteria.

 

[jklol]

What the fuck was that dawg

 

[okkk]

I could not do that stupid square question for my life

 

[tgone]

I could not do that stupid square question for my life

I spent like 20 minutes on that and I finally got it after just staring for so long

 

[Longbottom]

I spent like 20 minutes on that and I finally got it after just staring for so long

Bruh how, q16 b took too long I gave up on it

 

[tgone]

Bruh how, q16 b took too long I gave up on it

you can write “vector” CB = e^(ipi/3)CA since it’s equilateral
i’m just going to use zA=a, zB=b, zC=c
i.e.
b-c=(a-c) e^(ipi/3)
so b=c(1-e^(ipi/3))+ae^(ipi/3)

we know that:
b=xb+5i
c=xc-5i

subbing c and a into above the expression for b, you get an expression for b in terms of xc, and you can solve for xc by using Im(b)=5

 

[Deem_Skills]

Good luck guys

moments before disaster

 

[Trebla]

Check out Q6a) from 2005 HSC…

@tgone wtf they actually asked the same question as this in this year’s HSC (with minor variations)….

 

[tgone]

@tgone wtf they actually asked the same question as this in this year’s HSC (with minor variations)….

yeah literally i looked at it in reading time and did a double take … thought what the heck did he know about it… so glad i did it thank you so much

 

[tgone]

@tgone wtf they actually asked the same question as this in this year’s HSC (with minor variations)….

although to be fair when you sent I just skimmed over it and thought yeah I think I can do this after a bit of thinking so it just made it quicker in the test rather than letting me know how to do it

 

[yanujw]

yeah literally i looked at it in reading time and did a double take … thought what the heck did he know about it… so glad i did it thank you so much

Same lol it took me by surprise when I first saw it, thinking about how it looked really similar

 

[synthesisFR]

To try find the substitutions the trick is often to try match up the powers. For example, if I was like prove that a^4+b^4+c^4>abc(a+b+c), you see the 4th power so instantly you're thinking along the lines of Am-Gm for four. Then, you see three terms on the LHS and you notice that on the RHS you've got a^2bc, so a is twice the power. Therefore a good guess would be Am-Gm for a^4+a^4+b^4+c^4≥4a^2bc. And you'll find that this works out if you to it for b and c and add them together. Like fr it's tricky but there are some hints in the question itself and it helps you narrow it down to like a couple guesses. Idk if this helps

Question
R u allowed to just use am hm of threes or fours without proving it first