Run hard@thehsc
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- HSC
- 2022
For the HSC 3u and 4u sample answers, can there be more than one way of getting the correct answer apart from the sample answer given in the marking guidelines?
Yes as long as it is within the scope of the syllabusFor the HSC 3u and 4u sample answers, can there be more than one way of getting the correct answer apart from the sample answer given in the marking guidelines?
Yes you canYes as long as it is within the scope of the syllabus
You can't however use MX1 techniques for ADV questions or MX2 techniques for MX1 questions
i think for some identities that are outside the syllabus, you have to derive them right?Yes you can
I do not think you can use MX2 techniques for MX1 tho - personally tried it out and I got penalised... Not sure about MX1 and Maths Advanced!Yes you can
may i ask what was the technique and question?I do not think you can use MX2 techniques for MX1 tho - personally tried it out and I got penalised... Not sure about MX1 and Maths Advanced!
I do not think you can use MX2 techniques for MX1 tho - personally tried it out and I got penalised... Not sure about MX1 and Maths Advanced!
I've asked my teachers as well and they said yesi think for some identities that are outside the syllabus, you have to derive them right?
I have used it mainly for integration techniques (4u in 3u and 3u in 2u)may i ask what was the technique and question?
ah okay thats cool, using 4u integration techniques would probably give you an advantage. but don't they design the exams so that you don't need 4u in 3u exams? i wonder if this is allowed in the actual hscI have used it mainly for integration techniques (4u in 3u and 3u in 2u)
No there was definitely another way to do it, I just thought by parts was easier. It was to integrate x(cos^-1x) or something like thatah okay thats cool, using 4u integration techniques would probably give you an advantage. but don't they design the exams so that you don't need 4u in 3u exams? i wonder if this is allowed in the actual hsc
ig you could use the differentiate then integrate method in this case - but by parts would be the obvious choice ig!No there was definitely another way to do it, I just thought by parts was easier. It was to integrate x(cos^-1x) or something like that