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Help Binomial Question (2 Viewers)

notme123

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Make sure that you understand how these questions work as they can be given in different forms that cause major difficulties if a wrote-learned algorithmic approach does not match the question form.
how else can this question be asked? it seems the method would always be the same
 

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When looking at the HSC past questions and Baulkham Hill's 2020 year 11 ext yearly the types of ways the question can be asked are:
1. constant term
2. coefficient of specific index
3. coefficient of x^3 in (1 + x + x^2)^5
4. I don't even know how to summarise the next question.
1631345192473.png
 

notme123

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When looking at the HSC past questions and Baulkham Hill's 2020 year 11 ext yearly the types of ways the question can be asked are:
1. constant term
2. coefficient of specific index
3. coefficient of x^3 in (1 + x + x^2)^5
4. I don't even know how to summarise the next question.
View attachment 32064
For 3., i know you can make it binomial through grouping but whats a more efficient method
 

Life'sHard

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For 3., i know you can make it binomial through grouping but whats a more efficient method
There is a method, I just don't know how to explain it without having to learn latex to type it out lol.
 

notme123

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the eddie woo method doesnt work for the second one unless i am clincally idiotic can someone pls help me?
 

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notme123

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ExtremelyBoredUser

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Alright, I'll upload my working out. I'll use my phone since its quicker. Someone check it because Binomial and Combinatorics aren't exactly my strong suit.
 

ExtremelyBoredUser

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20210911_215941.jpg

Apologies for my working out, I just quickly rushed solving the problem.

For some faded parts:
In line 2: - 10!/k!*(10-k)!, in this line i also cancelled out the negatives

On that note, I also struggle with this topic a bit so if anyone in the forum could answer this;

How do you know which term is a and b in the binomial expansion? Sometimes the formula works if the a term is the coefficient of x and vice versa. I'm confused by that so if someone could clarify that, it would be nice.
 
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