• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Equations word problems (1 Viewer)

kpad5991

Member
Joined
Dec 29, 2016
Messages
238
Gender
Male
HSC
2018
Please can you show working for the following:

a) At a sale, Sarah spent $143 on some shirts and shorts. The shirts cost $15 each and the shorts cost $17 each. What is the total number of shirts and shorts that Sarah bought?

b) Bill sits for a test containing 20 questions. He gets 2 marks for each correct answer and loses 1 mark for each incorrect answer. He scored 22 marks in the test. How many questions did he get correct?

c) Fred is twice as old as his son and Fred is 36 years older than his son. How old is Fred?

d) Mina earns $3600 more than Betty and Lina earns $2000 less than Betty. If the total of the three incomes is $151 600, find the incomes of each person.
 

Etho_x

Joined
Jun 21, 2019
Messages
822
Location
Sydney
Gender
Male
HSC
N/A
a didn’t stick out to me at first so I did b, c, and d first lol
4BAF1BDD-F9EE-4ACD-92B3-F518F9A55784.png29E81159-8C51-4B38-A9DB-B39514162D86.jpeg2FBDA72D-514D-4D9F-9AC9-AD09F06E3DE9.jpeg
 

Etho_x

Joined
Jun 21, 2019
Messages
822
Location
Sydney
Gender
Male
HSC
N/A
For a though, I thought it was just easier to do process by elimination since it would be a reasonably small number for both. We know 15A + 17B = 143, where A is the number of shirts and B is the number of shorts bought.

Rearranging for A: (143-17B)/15 = A
By process of elimination, the result yielding both whole numbers is when B = 4 and A = 5, that is, the person bought 5 shirts and 4 shorts.
 

kpad5991

Member
Joined
Dec 29, 2016
Messages
238
Gender
Male
HSC
2018
For a though, I thought it was just easier to do process by elimination since it would be a reasonably small number for both. We know 15A + 17B = 143, where A is the number of shirts and B is the number of shorts bought.

Rearranging for A: (143-17B)/15 = A
By process of elimination, the result yielding both whole numbers is when B = 4 and A = 5, that is, the person bought 5 shirts and 4 shorts.
What will the second equation be?
 

Qeru

Well-Known Member
Joined
Dec 30, 2020
Messages
368
Gender
Male
HSC
2021
Please can you show working for the following:

a) At a sale, Sarah spent $143 on some shirts and shorts. The shirts cost $15 each and the shorts cost $17 each. What is the total number of shirts and shorts that Sarah bought?

b) Bill sits for a test containing 20 questions. He gets 2 marks for each correct answer and loses 1 mark for each incorrect answer. He scored 22 marks in the test. How many questions did he get correct?

c) Fred is twice as old as his son and Fred is 36 years older than his son. How old is Fred?

d) Mina earns $3600 more than Betty and Lina earns $2000 less than Betty. If the total of the three incomes is $151 600, find the incomes of each person.
where x and y are positive integers. This is a linear diophantine equation. For the purposes of HSC guess and check works. However the way we solve these types of equations is as follows:
Take the euclidean algorithm to find gcd(15,17):
17 = 15(1) + 2
15 = 2(7) + 1
2 = 1(2) + 0
So gcd(15,17)=1
Then write 1 as a linear combination of 15 and 17 (by reversring the euclidean algorithm above):
i.e. 1=15-2(7)=15-(17-15)(7)=8(15)-7(17)

So:

Then simply multiply both sides of the equation by 143 to get:


So a solution is:
But notice how:
So our general sols are: where n is any integer.
Now we want positive x and y solutions so: and . So our only solution is when n=67 i.e. .
 

Etho_x

Joined
Jun 21, 2019
Messages
822
Location
Sydney
Gender
Male
HSC
N/A
where x and y are positive integers. This is a linear diophantine equation. For the purposes of HSC guess and check works. However the way we solve these types of equations is as follows:
Take the euclidean algorithm to find gcd(15,17):
17 = 15(1) + 2
15 = 2(7) + 1
2 = 1(2) + 0
So gcd(15,17)=1
Then write 1 as a linear combination of 15 and 17 (by reversring the euclidean algorithm above):
i.e. 1=15-2(7)=15-(17-15)(7)=8(15)-7(17)

So:

Then simply multiply both sides of the equation by 143 to get:


So a solution is:
But notice how:
So our general sols are: where n is any integer.
Now we want positive x and y solutions so: and . So our only solution is when n=67 i.e. .
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top