Skuxxgolfer
Member
- Joined
- Aug 13, 2018
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- 35
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Literally 5s of googling will tell you that this integral cannot be expressed using elementary analytical functions. If you plug this into wolframalpha, you can get the result in terms of an elliptic integral.
Especially stupid_girls integrals. My friend and I tried the last one but couldn't get it out.I like how the thread originally started with "Post integration questions within scope of MX2", but now it's just whatever goes haha.
Thanks! The hero we need, but not the one we deserve. Not sure what tex commands and packages are recognised since \begin{enumerate} didn't work so I had to keep testing and spectacularly failing.These are Mr Blyatman's question. Ill work them up later today
Yes I just checked it on wolfram, its 1/2. Answer in the book must've been wrong. Will update post.For no 2 im getting 1/2. Can someone check? Probs a typo
What book are these questions from?Yes I just checked it on wolfram, its 1/2. Answer in the book must've been wrong. Will update post.
Yeah it's pretty easy to do that one (as well as the others) using contour integrals and the residue theorem - takes like 5-10 lines. But I was seeing if these can be done using mx2 level (or similar), so I just put them out there for the community to solve. For this one, you could factorise 1+x^4 into it's quadratic terms (using complex numbers) then using partial fractions. Haven't tried it but that's how I'd go about it.3rd one was tooo hard.
Had a peek at it. Got up to sophie germains and gave up
They're taken from a graduate-level maths textbook that was used in a math course I did last semester. I didn't mention it at first since I didn't want to discourage people from attempting them. But yes, full disclosure: I'm trying to see how these would be solved "normally" and see how much working would be involved compared to using complex analysis. I'm also trying to see if there's an integral that is impossible to solve conventionally and can ONLY be solved using complex analysis.What book are these questions from?
Nice one, didn't think of that haha, trivial using a smart substitution!
Admittedly, I went through a lengthy process (including looking up a standard integral table for ) and it was only at the end I realised that everything I did could be compressed into one substitution.Nice one, didn't think of that haha, trivial using a smart substitution!
These are all beyond the scope of the syllabus.