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Bongo · Feb 12, 2019

Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4).

The answer from the textbook is 4 ln 4 * x- y+ 4=0 .

I'm not sure how to get that answer. Any help will be greatly appreciated.

InteGrand · Feb 12, 2019

Bongo said:
Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4).

The answer from the textbook is 4 ln 4 * x- y+ 4=0 .

I'm not sure how to get that answer. Any help will be greatly appreciated.

$\noindent The point $(0, 4)$ does not lie on that curve, because $4^{0} + 1 \neq 4$.$

InteGrand · Feb 12, 2019

Bongo said:
Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4).

The answer from the textbook is 4 ln 4 * x- y+ 4=0 .

I'm not sure how to get that answer. Any help will be greatly appreciated.

$\noindent In general though, to find the equation of a tangent line at the point $(a, f(a))$ on the graph $y = f(x)$, all you need to work out is the slope of the tangent line. Once you know this, since you know a point on the line as well (namely $(a,f(a))$), you can write down the equation of the line. (This is because if we know the slope and a point on a line, then we can write down its equation.)$

$\noindent As long as you know how to differentiate the function $f(x) = 4^{x} + 1$, you should have the tools required to find equations of tangents on the given curve.$

Need help (1 Viewer)

Bongo

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InteGrand

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InteGrand

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