I need some help with a math problem. (1 Viewer)

Whicanti · Oct 19, 2016

Screen Shot 2016-10-19 at 11.36.37 pm.png

So far i've been able to deduce that 12/x^-4 > 0

Beyond that i'm stuck.

Edit 1: Okay, so if i sub in any number besides 0 into x^4, i always get a number greater than 0. I think this means that 2/x^2 is concave up for all x cant equal 0. Dunno though.

InteGrand · Oct 19, 2016

Whicanti said:
View attachment 33524

So far i've been able to deduce that 12/x^-4 > 0

Beyond that i'm stuck.

$\noindent That's basically it. Since the second derivative is $f''(x) = 12x^{-4}>0$ for all $x\neq 0$, $f$ is concave up everywhere other than $x=0$.$

I need some help with a math problem. (1 Viewer)

Whicanti

New Member

InteGrand

Well-Known Member

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