MedVision ad

Need help. (2 Viewers)

123ryoma12

Member
Joined
Apr 14, 2015
Messages
60
Gender
Male
HSC
2016
Capture.PNG
Ok, so the question isn't the problem but rather the method used to get the answer.
This is the answer:
Capture.PNG
Why is it that we're allowed to take the modulus of both sides to get a locus because if I do the same with a fixed point for example:
z = 1 + i
|z| = sqrt(2)
x^2 + y^2 = 2
I get that locus, which is obviously wrong because z is a fixed point.
 

Paradoxica

-insert title here-
Joined
Jun 19, 2014
Messages
2,556
Location
Outside reality
Gender
Male
HSC
2016
View attachment 33512
Ok, so the question isn't the problem but rather the method used to get the answer.
This is the answer:
View attachment 33513
Why is it that we're allowed to take the modulus of both sides to get a locus because if I do the same with a fixed point for example:
z = 1 + i
|z| = sqrt(2)
x^2 + y^2 = 2
I get that locus, which is obviously wrong because z is a fixed point.
Your "counterexample" doesn't work because there is no variable.

In the question you are flummoxing over, there are two variables, and you are given the behaviour of one.

The relation between the variables is given and you are asked to determine the behaviour of the dependent variable.
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
View attachment 33512
Ok, so the question isn't the problem but rather the method used to get the answer.
This is the answer:
View attachment 33513
Why is it that we're allowed to take the modulus of both sides to get a locus because if I do the same with a fixed point for example:
z = 1 + i
|z| = sqrt(2)
x^2 + y^2 = 2
I get that locus, which is obviously wrong because z is a fixed point.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top