By definition of cos and sin.Does anyone ere know why a cos wave starts from 1 and why a sine wave starts from 0
Thanks
Read your textbookDoes anyone ere know why a cos wave starts from 1 and why a sine wave starts from 0
Thanks
Yes lol...It says the max and min value of sinx and cosx and 1 and -1 respectively so we say their amplitude in 1
@Integrand, by definition of a cos wave, it starts at one
By definition of a sine wave, it starts at 0
Please correct me if I am wrong (I can't find it in the textbook)
Thanks
By convention.Does anyone ere know why a cos wave starts from 1 and why a sine wave starts from 0
Thanks
ThanksYes lol...
Literally punch sin(0) and cos(0) into your calculator.
If you want the formal geometric interpretation that's a tiny bit harder.
The textbooks sometimes don't really go through the definition of cos and sin (I do think they are in the Year 11 3U Pender (Cambridge) Textbook though, so check that out if you have it). For HSC purposes, for a real number t, cos(t) and sin(t) are defined as follows:It says the max and min value of sinx and cosx and 1 and -1 respectively so we say their amplitude in 1
@Integrand, by definition of a cos wave, it starts at one
By definition of a sine wave, it starts at 0
Please correct me if I am wrong (I can't find it in the textbook)
Thanks
ThanksThe textbooks sometimes don't really go through the definition of cos and sin. For HSC purposes, for a real number t, cos(t) is defined as follows:
Draw the unit circle in the Cartesian Plane (radius 1, centred at origin). Draw a ray from the origin making an angle t radians (counter-clockwise) from the positive x-axis. This ray cuts the circle at one (and only one) point P. Then the x-value of this point is defined as cos(t), and the y-value as sin(t).
In other words, cos(t) is the x-value of the point of intersection with the ray of angle t and the unit circle, and sin(t) is the y-value.
See for example this image: http://superintendentemily.weebly.com/uploads/2/3/5/1/23512632/5027961_orig.gif .
So using these definitions, you should be able to easily show that cos(0) = 1 and sin(0) = 0.
(If we use a circle of radius r instead of unit circle, we get instead cos(t) = x/r, and sin(t) = y/r, where (x,y) is the point of intersection with the aforementioned ray and the circle of radius r centred at the origin.)
WHY IS THE ORIGIN AT (0,0) and not (-2,7)?????Does anyone ere know why a cos wave starts from 1 and why a sine wave starts from 0
Thanks
You are falling into eyeseeyou's trap-it is probably exactly what he wants-to aggravate people by asking such questions. Just ignore him.WHY IS THE ORIGIN AT (0,0) and not (-2,7)?????
WHY IS THE Y INTERCEPT WHEN X=0 AND NOT WHEN X=-23??
WHY IS WHY CALLED WHY????
WHY ARE YOU ASKING SUCH MUNTED QUESTIONS LMAO???
The existential crisis is realWHY IS THE ORIGIN AT (0,0) and not (-2,7)?????
WHY IS THE Y INTERCEPT WHEN X=0 AND NOT WHEN X=-23??
WHY IS WHY CALLED WHY????
WHY ARE YOU ASKING SUCH MUNTED QUESTIONS LMAO???
Expand everything and equate coefficients.Express x(x-1) in the form p+q(x-1)+r(x-1)^2
I am not sure what the question is asking me to do here.
Express x(x-1) in the form p+q(x-1)+r(x-1)^2
I am not sure what the question is asking me to do here.
Another method is to complete the square:Express x(x-1) in the form p+q(x-1)+r(x-1)^2
I am not sure what the question is asking me to do here.