Prelim 2016 Maths Help Thread (1 Viewer)

[leehuan]

You got a right but for b it was a=-1 and for some reason I can't find C there

Of course acceleration = -1. Did you sub t=0 in?
______________

To find C, use what the question said.

The question explicitly states when t=0, x=0

 

[eyeseeyou]

Of course acceleration = -1. Did you sub t=0 in?
______________

To find C, use what the question said.

The question explicitly states when t=0, x=0

ty for your help leehuan

 

[InteGrand]

yeah but the parabola isn'tsupposed to cross into the negative side

Why not?

 

[davidgoes4wce]

I thought the parabola could cross the negative. Didn't mention anywhere in the question that the distance was 'always to the right'.

 

[eyeseeyou]

Why not?

And now Integrand comes to the rescue after so long...lol

because the answer sheet shows that it doesn't cross into the negative side

 

[eyeseeyou]

And now Integrand comes to the rescue after so long...lol

because the answer sheet shows that it doesn't cross into the negative side

But I think it can...I'm pretty sure it can

 

[InteGrand]

And now Integrand comes to the rescue after so long...lol

because the answer sheet shows that it doesn't cross into the negative side

 

[Shuuya]

And now Integrand comes to the rescue after so long...lol

because the answer sheet shows that it doesn't cross into the negative side

You mean that t is greater than/equal to 0 right? Because time can't be negative.

 

[InteGrand]

You mean that t is greater than/equal to 0 right? Because time can't be negative.

Ah. I'd thought eyeseeyou was referring to crossing the horizontal axis. Yeah, should only draw it for t ≥ 0.

 

[eyeseeyou]

You mean that t is greater than/equal to 0 right? Because time can't be negative.

yeah...I think so

 

[eyeseeyou]

Ah. I'd thought eyeseeyou was referring to crossing the horizontal axis. Yeah, should only draw it for t ≥ 0.

Oh yeah wasn't aware of that lol

 

[eyeseeyou]

Did no one help me with my last question!!!

 

[InteGrand]

Did no one help me with my last question!!!

Looks like no-one did yet. But that's a 4U type question (I think). Are you already up to 4U?

 

[eyeseeyou]

Looks like no-one did yet. But that's a 4U type question (I think). Are you already up to 4U?

No I'm not Integrand

 

[eyeseeyou]

Did anyone help me with Q2 or Q3?

 

[eyeseeyou]

BTW thanks for the help guys

Really appreciated it

If I didn't ask I wold've been dead

 

[InteGrand]

BTW thanks for the help guys

Really appreciated it

If I didn't ask I wold've been dead

Why would you be dead if you hadn't asked? You could've always asked your teacher or someone tomorrow if no-one had been able to help here, couldn't you?

 

[davidgoes4wce]

 

[leehuan]

I already did Q4, and it said to find the acceleration when t=0

 

[davidgoes4wce]

I read the question the other way around. My bad.