quick Q's (1 Viewer)

Green Yoda · Nov 28, 2015

How is this a polynomial?

InteGrand · Nov 28, 2015

Rathin said:
View attachment 32692
How is this a polynomial?

$For $x\neq 0$, we can simplify it to $9x^2 + x+1$, which is a polynomial in $x$.$

Green Yoda · Nov 28, 2015

InteGrand said:
$For $x\neq 0$, we can simplify it to $9x^2 + x+1$, which is a polynomial in $x$.$

dont quite understand that..
the x is on the denominator so its power is negative..so it would not be a polynomial?

InteGrand · Nov 28, 2015

Rathin said:
dont quite understand that..
the x is on the denominator so its power is negative..so it would not be a polynomial?

$If $x\neq 0$, we can just simplify it (if $x=0$, the expression is undefined). For example, we can simplify something like $\frac{x^3}{x}$ to $x^2$ if $x\neq 0$ (basically index laws; `cancel' an $x$ from the numerator and denominator to be left with $\frac{x^2}{1}$, which is $x^2$). A similar idea is used in the specific question you gave.$

Green Yoda · Nov 28, 2015

InteGrand said:
$If $x\neq 0$, we can just simplify it (if $x=0$, the expression is undefined). For example, we can simplify something like $\frac{x^3}{x}$ to $x^2$ if $x\neq 0$ (basically index laws; `cancel' an $x$ from the numerator and denominator to be left with $\frac{x^2}{1}$, which is $x^2$). A similar idea is used in the specific question you gave.$

ahhhhh got it, thanks.

quick Q's (1 Viewer)

Green Yoda

Hi Φ

InteGrand

Well-Known Member

Green Yoda

Hi Φ

InteGrand

Well-Known Member

Green Yoda

Hi Φ

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