Geometry (1 Viewer)

Green Yoda · Nov 10, 2015

ugh fk geometry, help pls.

InteGrand · Nov 10, 2015

Rathin said:
View attachment 32666

ugh fk geometry, help pls.

$Note that $\angle BAO = x^\circ$ and $\angle OCB = y^\circ$ (this is because triangles $BAO$ and $BCO$ are isosceles, as they contain two equal sides each (equal radii of the circle $AO$, $BO$ and $CO$) (and base angles of isosceles triangles are equal)), so $x^\circ + x^\circ+y^\circ + y^\circ=180^\circ$ (angle sum of triangle $ABC$), so $x^\circ + y^\circ = 90^\circ$, and so $\angle ABC = 90^\circ$, as required.$

Green Yoda · Nov 10, 2015

InteGrand said:
$Note that $\angle BAO = x^\circ$ and $\angle OCB = y^\circ$ (this is because triangles $BAO$ and $BCO$ are isosceles, as they contain two equal sides each (equal radii of the circle $AO$, $BO$ and $CO$) (and base angles of isosceles triangles are equal)), so $x^\circ + x^\circ+y^\circ + y^\circ=180^\circ$ (angle sum of triangle $ABC$), so $x^\circ + y^\circ = 90^\circ$, and so $\angle ABC = 90^\circ$, as required.$

oh yeah bloody isosceles triangle..thanks

leehuan · Nov 10, 2015

Rathin said:
oh yeah bloody isosceles triangle..thanks

Take the tip

circles (especially in 2U...but in 3U as well...) usually imply equal radii somehow.

Geometry (1 Viewer)

Green Yoda

Hi Φ

InteGrand

Well-Known Member

Green Yoda

Hi Φ

leehuan

Well-Known Member

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